numpy.floor(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'floor'>
按照元素的方式返回输入的下限。
标量x的底部是最大的整数i，使得i <= x。 它通常表示为\ lfloor x \ rfloor。
Parameters:
x : array_like
Input data.
out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
**kwargs
For other keyword-only arguments, see the ufunc docs.
Returns:
y : ndarray or scalar
The floor of each element in x.
Notes
一些电子表格程序计算“floor-to-zero”,换一种说法 floor(-2.5) == -2.
NumPy instead uses the definition of floor where floor(-2.5) == -3.
Examples
In [2]: import numpy as np
In [3]: a = np.array([-1.7, -1.5, -0.2, 0.2, 1.5, 1.7, 2.0])
In [4]: np.floor(a)
Out[4]: array([-2., -2., -1., 0., 1., 1., 2.])
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