我想制作这个
[
{name: "james", age: 10},
{name: "john", age: 12},
{name: "johnny", age: 56}
]
我的下面的代码失败了，得到了预期的令牌吗？
let x = [
{name: "james", age: 10, school: "London"},
{name: "john", age: 12, school: "India"},
{name: "johnny", age: 56, school: "USA"}
]
let y = x.map(obj => {name:obj.name, age:obj.age})
console.log(y)
你错过了()像这样改变({name:obj.name, age:obj.age})
您必须将返回的对象文字括在括号中。否则
大括号将被视为表示函数体。下一个
作品：
参考问题 https://stackoverflow.com/questions/28770415/ecmascript6-arrow-function-that-returns-an-object
let x = [
{name: "james", age: 10, school: "London"},
{name: "john", age: 12, school: "India"},
{name: "johnny", age: 56, school: "USA"}
]
let y = x.map(obj => ({name:obj.name, age:obj.age}))
console.log(y)
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