格式化多维数组 Python

如何编写代码来更改多维数组中每个单独数组的值a出现负值后立即归零。所以里面的第二个数组a有负值[12,34,5,6,88,-10,30,75]-10 会将其所有值及其后的值转为零。将数组变成[12,34,5,6,88,0,0,0]。我怎样才能获得预期的输出？

import numpy as np 

a = np.array([[12,45,50,60,30],
             [12,34,5,6,88,-10,30,75],
             [3,45,332,45,-12,-4,-64,12],
             [12,45,3,22,323]])

预期输出：

[[12,45,50,60,30],
 [12,34,5,6,88,0,0,0],
 [3,45,332,45,0,0,0,0],
 [12,45,3,22,323]]

尝试这个：

import numpy as np 

a = np.array([[12,45,50,60,30],
             [12,34,5,6,88,-10,30,75],
             [3,45,332,45,-12,-4,-64,12],
             [12,45,3,22,323]], dtype='object')


for l in a:
    for i in l:
        if i<0:
            l[l.index(i):] = [0] * len(l[l.index(i):])
            
a

output:

array([list([12, 45, 50, 60, 30]), list([12, 34, 5, 6, 88, 0, 0, 0]),
       list([3, 45, 332, 45, 0, 0, 0, 0]), list([12, 45, 3, 22, 323])],
      dtype=object)

第二种解决方案：

import numpy as np 

def neg_to_zero(l):
    for i in l:
        if i<0:
            l[l.index(i):] = [0] * len(l[l.index(i):])

a = np.array([[12,45,50,60,30],
             [12,34,5,6,88,-10,30,75],
             [3,45,332,45,-12,-4,-64,12],
             [12,45,3,22,323]], dtype='object')

list(map(neg_to_zero, a))

a