我在我的网站上使用谷歌登录：
<script src="https://apis.google.com/js/platform.js" async defer></script>
<script>
function onSignIn(googleUser) {
var profile = googleUser.getBasicProfile();
//console.log('ID: ' + profile.getId()); // Do not send to your backend! Use an ID token instead.
//console.log('Image URL: ' + profile.getImageUrl());
//console.log('Name: ' + profile.getName());
//console.log('Email: ' + profile.getEmail());
var user_uname = profile.getName();
var user_email = profile.getEmail();
alert(user_uname);
}
</script>
这是登录谷歌的按钮：
<div class="g-signin2" data-onsuccess="onSignIn"></div>
我想为用户提供谷歌登录功能，但问题是每当页面加载时 onSignIn() 函数都会自动调用。
我只需要单击按钮即可。有谁能够帮助我？
最佳解决方案是仅在用户未登录时呈现登录按钮。
<html>
<head>
<meta name="google-signin-client_id" content="YOUR_CLIENT_ID">
</head>
<body>
<script>
function onSignIn(googleUser) {
var profile = googleUser.getBasicProfile();
var user_name = profile.getName();
alert(user_name);
}
function onLoad() {
gapi.load('auth2,signin2', function() {
var auth2 = gapi.auth2.init();
auth2.then(function() {
// Current values
var isSignedIn = auth2.isSignedIn.get();
var currentUser = auth2.currentUser.get();
if (!isSignedIn) {
// Rendering g-signin2 button.
gapi.signin2.render('google-signin-button', {
'onsuccess': 'onSignIn'
});
}
});
});
}
</script>
<div id="google-signin-button"></div>
<script src="https://apis.google.com/js/platform.js?onload=onLoad" async defer></script>
</body>
</html>
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