As of Swift 4(Xcode 9),Swift 标准
库提供了在 Swift 字符串范围之间进行转换的方法
(Range<String.Index>
) and NSString
范围(NSRange
)。
例子:
let str = "a????b????????c"
let r1 = str.range(of: "????????")!
// String range to NSRange:
let n1 = NSRange(r1, in: str)
print((str as NSString).substring(with: n1)) // ????????
// NSRange back to String range:
let r2 = Range(n1, in: str)!
print(str[r2]) // ????????
因此,文本字段委托方法中的文本替换
现在可以做为
func textField(_ textField: UITextField,
shouldChangeCharactersIn range: NSRange,
replacementString string: String) -> Bool {
if let oldString = textField.text {
let newString = oldString.replacingCharacters(in: Range(range, in: oldString)!,
with: string)
// ...
}
// ...
}
(Swift 3 及更早版本的旧答案:)
从 Swift 1.2 开始,String.Index
有一个初始化程序
init?(_ utf16Index: UTF16Index, within characters: String)
可以用来转换NSRange
to Range<String.Index>
正确地
(包括表情符号、区域指标或其他扩展的所有情况
字素簇)无需中间转换为NSString
:
extension String {
func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
let from16 = advance(utf16.startIndex, nsRange.location, utf16.endIndex)
let to16 = advance(from16, nsRange.length, utf16.endIndex)
if let from = String.Index(from16, within: self),
let to = String.Index(to16, within: self) {
return from ..< to
}
return nil
}
}
该方法返回一个optional字符串范围,因为并非全部NSRange
s
对于给定的 Swift 字符串有效。
The UITextFieldDelegate
委托方法可以写为
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
if let swRange = textField.text.rangeFromNSRange(range) {
let newString = textField.text.stringByReplacingCharactersInRange(swRange, withString: string)
// ...
}
return true
}
逆变换为
extension String {
func NSRangeFromRange(range : Range<String.Index>) -> NSRange {
let utf16view = self.utf16
let from = String.UTF16View.Index(range.startIndex, within: utf16view)
let to = String.UTF16View.Index(range.endIndex, within: utf16view)
return NSMakeRange(from - utf16view.startIndex, to - from)
}
}
一个简单的测试:
let str = "a????b????????c"
let r1 = str.rangeOfString("????????")!
// String range to NSRange:
let n1 = str.NSRangeFromRange(r1)
println((str as NSString).substringWithRange(n1)) // ????????
// NSRange back to String range:
let r2 = str.rangeFromNSRange(n1)!
println(str.substringWithRange(r2)) // ????????
Swift 2 更新:
Swift 2 版本rangeFromNSRange()
已经给出了
作者:谢尔希·雅科文科这个答案 https://stackoverflow.com/a/32379600/1187415,我把它包括在内
为了完整性,这里:
extension String {
func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
let from16 = utf16.startIndex.advancedBy(nsRange.location, limit: utf16.endIndex)
let to16 = from16.advancedBy(nsRange.length, limit: utf16.endIndex)
if let from = String.Index(from16, within: self),
let to = String.Index(to16, within: self) {
return from ..< to
}
return nil
}
}
Swift 2 版本NSRangeFromRange()
is
extension String {
func NSRangeFromRange(range : Range<String.Index>) -> NSRange {
let utf16view = self.utf16
let from = String.UTF16View.Index(range.startIndex, within: utf16view)
let to = String.UTF16View.Index(range.endIndex, within: utf16view)
return NSMakeRange(utf16view.startIndex.distanceTo(from), from.distanceTo(to))
}
}
Swift 3 (Xcode 8) 更新:
extension String {
func nsRange(from range: Range<String.Index>) -> NSRange {
let from = range.lowerBound.samePosition(in: utf16)
let to = range.upperBound.samePosition(in: utf16)
return NSRange(location: utf16.distance(from: utf16.startIndex, to: from),
length: utf16.distance(from: from, to: to))
}
}
extension String {
func range(from nsRange: NSRange) -> Range<String.Index>? {
guard
let from16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location, limitedBy: utf16.endIndex),
let to16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location + nsRange.length, limitedBy: utf16.endIndex),
let from = from16.samePosition(in: self),
let to = to16.samePosition(in: self)
else { return nil }
return from ..< to
}
}
Example:
let str = "a????b????????c"
let r1 = str.range(of: "????????")!
// String range to NSRange:
let n1 = str.nsRange(from: r1)
print((str as NSString).substring(with: n1)) // ????????
// NSRange back to String range:
let r2 = str.range(from: n1)!
print(str.substring(with: r2)) // ????????