在 .NET Core MVC 应用程序中使用 TempData 时出现错误 500

你好，我正在尝试添加一个对象TempData并重定向到另一个控制器操作。我在使用时收到错误消息 500TempData.

public IActionResult Attach(long Id)
{
    Story searchedStory=this.context.Stories.Find(Id);
    if(searchedStory!=null)
    {
        TempData["tStory"]=searchedStory;  //JsonConvert.SerializeObject(searchedStory) gets no error and passes 

        return RedirectToAction("Index","Location");
    }
    return View("Index");
}


public IActionResult Index(object _story) 
{             
    Story story=TempData["tStory"] as Story;
    if(story !=null)
    {
    List<Location> Locations = this.context.Locations.ToList();
    ViewBag._story =JsonConvert.SerializeObject(story);
    ViewBag.rstory=story;
    return View(context.Locations);
    }
    return RedirectToAction("Index","Story");
}

P.S 阅读我添加的可能解决方案app.UseSession() to the Configure方法和services.AddServices() in the ConfigureServices方法但无济于事。有什么我必须注意的晦涩设置吗？

P.S添加ConfigureServices and UseSession

配置服务

 public void ConfigureServices(IServiceCollection services)
            {
                services.AddOptions();
                services.AddDbContext<TreasureContext>(x=>x.UseMySql(connectionString:Constrings[3]));
                services.AddMvc();
                services.AddSession();
            }

配置

public void Configure(IApplicationBuilder app, IHostingEnvironment env)
        {
            if (env.IsDevelopment())
            {
                app.UseDeveloperExceptionPage();
            }
            else
            {
                app.UseExceptionHandler("/Home/Error");
            }

            app.UseStaticFiles();
            app.UseSession();

            app.UseMvc(routes =>
            {
                routes.MapRoute(
                    name: "default",
                    template: "{controller=Home}/{action=Index}/{id?}");
            });
        }

您必须先序列化对象，然后再将其分配给 TempData，因为核心仅支持字符串而不支持复杂对象。

TempData["UserData"] = JsonConvert.SerializeObject(searchedStory);

并通过反序列化来检索对象。

var story = JsonConvert.DeserializeObject<Story>(TempData["searchedStory"].ToString())