我正在尝试使用 python 3.2 SMTPlib.sendmail() 函数
对 SMTP 库进行一些修改后(即
注释掉抑制错误消息的 rset() 函数)
我设法从服务器检索到以下错误消息:
发送邮件失败
(554,b'交易失败:由于可能滥用,无法发送消息;请访问http://postmaster.yahoo.com/abuse_smtp.html http://postmaster.yahoo.com/abuse_smtp.html了解更多信息')
雅虎邮件 SMTP 服务器认为我正在发送垃圾邮件,该 URL 确实链接到任何内容
有用。我认为这与标题不足有关,我似乎找不到明确的
回答什么是合规标头,我读过 Gmail 的类似问题。
模拟电子邮件已取代此帖子。
任何帮助,将不胜感激
我的完整代码如下:
self.message = email.message_from_string('''To: <[email protected] /cdn-cgi/l/email-protection>
From: <[email protected] /cdn-cgi/l/email-protection>
Reply-To: <[email protected] /cdn-cgi/l/email-protection>
Subject: Test send mail \n\n Hello''')
fromAddress = '[email protected] /cdn-cgi/l/email-protection'
toAddress = '[email protected] /cdn-cgi/l/email-protection'
try:
self.smtp = SMTP()
self.smtp.connect('smtp.mail.yahoo.com')
except Exception:
print('Connection Failed')
print(traceback.format_exc())
try:
self.smtp.login('rwilson','tree22')
except Exception:
print('Login Failed!')
print(traceback.format_exc())
try:
self.smtp.sendmail(fromAddress,toAddress ,self.message.as_string())
print("Message sucessfully sent!")
self.smtp.close()
except Exception as e:
print('SendMail Failed')
print(e)
以下内容适用于 Python 2.7 和 Python 3.2 上的 microsoft、google、yahoo 帐户:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Send email via smtp_host."""
import smtplib
from email.mime.text import MIMEText
from email.header import Header
####smtp_host = 'smtp.live.com' # microsoft
####smtp_host = 'smtp.gmail.com' # google
smtp_host = 'smtp.mail.yahoo.com' # yahoo
login, password = ...
recipients_emails = [login]
msg = MIMEText('body…', 'plain', 'utf-8')
msg['Subject'] = Header('subject…', 'utf-8')
msg['From'] = login
msg['To'] = ", ".join(recipients_emails)
s = smtplib.SMTP(smtp_host, 587, timeout=10)
s.set_debuglevel(1)
try:
s.starttls()
s.login(login, password)
s.sendmail(msg['From'], recipients_emails, msg.as_string())
finally:
s.quit()
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