我有一个很大的文本文件，每行都有可变数量的字段。每行中的第一个条目对应于一个生物途径，每个后续条目对应于该途径中的一个基因。前几行可能看起来像这样
path1 gene1 gene2
path2 gene3 gene4 gene5 gene6
path3 gene7 gene8 gene9
我需要将此文件作为列表读入 R，其中每个元素都是字符向量，列表中每个元素的名称是该行的第一个元素，例如：
> pathways <- list(
+ path1=c("gene1","gene2"),
+ path2=c("gene3","gene4","gene5","gene6"),
+ path3=c("gene7","gene8","gene9")
+ )
>
> str(pathways)
List of 3
$ path1: chr [1:2] "gene1" "gene2"
$ path2: chr [1:4] "gene3" "gene4" "gene5" "gene6"
$ path3: chr [1:3] "gene7" "gene8" "gene9"
>
> str(pathways$path1)
chr [1:2] "gene1" "gene2"
>
> print(pathways)
$path1
[1] "gene1" "gene2"
$path2
[1] "gene3" "gene4" "gene5" "gene6"
$path3
[1] "gene7" "gene8" "gene9"
...但我需要对数千行自动执行此操作。我看到一个之前发布过类似的问题 https://stackoverflow.com/questions/4843128/r-read-a-text-file-with-variable-number-of-columns-to-a-list，但我不知道如何从该线程中执行此操作。
提前致谢。
这是一种方法：
# Read in the data
x <- scan("data.txt", what="", sep="\n")
# Separate elements by one or more whitepace
y <- strsplit(x, "[[:space:]]+")
# Extract the first vector element and set it as the list element name
names(y) <- sapply(y, `[[`, 1)
#names(y) <- sapply(y, function(x) x[[1]]) # same as above
# Remove the first vector element from each list element
y <- lapply(y, `[`, -1)
#y <- lapply(y, function(x) x[-1]) # same as above
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