按 Ctrl+C 后，如何让 Python 在程序停止之前完成作业？

我有 4 个这样的工作的无限循环：

list1 = []
while 1:
    try:
        # job1
        a = B()
        # job2
        c = a.accd()
        # job3
        d = len(c)
        # job4
        list1.append(d)
    except KeyboardInterrupt:
        # save list1 into database(took long time)
        break

按 Ctrl + C 后，我无法确保它完成所有 4 项工作然后停止。

这似乎在睡眠时有效，但它有睡眠延迟。

list1 = []
while 1:
    try:
        # job1
        a = B()
        # job2
        c = a.accd()
        # job3
        d = len(c)
        # job4
        list1.append(d)
    except aaddcdcd:
        # some code here
    finally:
        try:
            time.sleep(3) # if I press Ctrl + C here it works perfectly
        except: KeyboardInterrupt:
            # save list1 into database(took long time)
            break

是否有可能在任何时候，当我按下某个键时，它都会执行此循环中的所有作业，更新数据库，然后停止。

好的，我有两个答案给你。

第一个答案

def jobOne():
    pass
def jobTwo():
    pass
def jobThree():
    pass
def jobFour():
    pass

interrupted    = False
finished       = False
jobs           = [jobOne, jobTwo, jobThree, jobFour]
jobsCarriedOut = [0] * len(jobs)
currentJob     = 0

while (not finished or not interrupted):
    try:
        jobs[currentJob]()
        jobsCarriedOut[currentJob] += 1

        currentJob += 1

        if currentJob == len(jobs):
            currentJob, finished = 0, True
        else:
            finished = False
    except KeyboardInterrupt:
        interrupted = True

print(jobsCarriedOut)

该作品将退出一次KeyboardInterrupt已被触发并且所有作业均已完成。

第二个答案

我只是简单地用谷歌搜索了一下禁用键盘中断Python并发现了这个如何覆盖键盘中断？ （Python） https://stackoverflow.com/a/6990487/4180176并提出了这个略有不同的代码。

import signal

def signal_handler(signal, frame):
    global interrupted
    interrupted = True

def jobOne():
    pass
def jobTwo():
    pass
def jobThree():
    pass
def jobFour():
    pass

interrupted    = False
finished       = False
jobs           = [jobOne, jobTwo, jobThree, jobFour]
jobsCarriedOut = [0] * len(jobs)
currentJob     = 0

signal.signal(signal.SIGINT, signal_handler)

while (not finished or not interrupted):
    jobs[currentJob]()
    jobsCarriedOut[currentJob] += 1
    currentJob += 1
    if currentJob == len(jobs):
        currentJob, finished = 0, True
    else:
        finished = False

print(jobsCarriedOut)

我从未使用过信号库（甚至听说过它），所以这里是文档 https://docs.python.org/2/library/signal.html

EDIT我从来没有使用过全局变量，所以我的用法可能是错误的。

EDIT TWO第一个示例由于没有捕获每一步的错误，因此只能在 80% 的时间内运行