如何使用 RestSharp 解析 JSON？

var client = new RestClient("http://10.0.2.2:50670/api");

var request = new RestRequest("Inventory", Method.GET);

request.OnBeforeDeserialization = resp => { resp.ContentType = "application/json"; };

// execute the request to return a list of InventoryItem
RestResponse<JavaList<InventoryItem>> response = (RestResponse<JavaList<InventoryItem>>)client.Execute<JavaList<InventoryItem>>(request);

返回的内容是一个 JSON 字符串，一个对象数组。以下是其简短摘录：

[{"Id":1,"Upc":"1234567890","Quantity":100,"Created":"2012-01-01T00:00:00","Category":"Tequila","TransactionType":"Audit","MetaData":"PATRON 750ML"},{"Id":2,"Upc":"2345678901","Quantity":110,"Created":"2012-01-01T00:00:00","Category":"Whiskey","TransactionType":"Audit","MetaData":"JACK DANIELS 750ML"},{"Id":3,"Upc":"3456789012","Quantity":150,"Created":"2012-01-01T00:00:00","Category":"Vodka","TransactionType":"Audit","MetaData":"ABSOLUT 750ml"}]

错误信息：

由于对象的当前状态，操作无效

这里有什么问题吗？我的InventoryItem与 JSON 字符串中的每个对象具有相同的属性。我是不是少了一步？

我怀疑 RestSharp 中使用的 SimpleJson 无法反序列化为 Java 列表。

首先我会尝试反序列化为：

List<InventoryItem>

如果做不到这一点，我建议ServiceStack.Text https://github.com/ServiceStack/ServiceStack.Text- .Net 最快的 JSON 库；并做：

var response = client.Execute(request);
var thingYouWant = JsonSerializer.DeserializeFromString<List<InventoryItem>>(response.Content);

这实际上是我自己做的。

编辑（感谢评论者）：在较新的版本中，现在是：

var deserializer = new JsonDeserializer();
deserializer.Deserialize<List<InventoryItem>>(response);