你可以使用itertools.groupby
:
import itertools as IT
import operator
seq = ['@', '2014', '00:03:01', 'Matt', '"login"', '0.01', '@', '2014', '02:06:12', 'Mary', '"login"', '0.01']
groups = (list(g) for k,g in IT.groupby(seq, lambda item: item=='@'))
print(list(IT.starmap(operator.add, IT.izip(*[groups]*2))))
prints
[['@', '2014', '00:03:01', 'Matt', '"login"', '0.01'], ['@', '2014', '02:06:12', 'Mary', '"login"', '0.01']]