tkinter：将多个按钮 lambda 映射到一个标签？

描述：我希望能够单击一个按钮并将其值发送到标签小部件（lab_1），我知道要执行一个按钮，您必须使用command=lambda: lab_1.configure(text=0)但是当我使用了一个标签时，你会如何将值打印到标签上for循环在嵌入列表中创建我的所有按钮。截至目前，所有按钮都有名为的变量key_press.

简化的问题：

• 如何将所有值写入我的标签（lab_1)?

• 你如何使用for循环，因此每次单击该按钮时，它都会向Label?

import tkinter as tk

root = tk.Tk()
# Change the original tkinter icon
root.iconbitmap('C:\\Users\\bmxfi\Downloads\images.ico')
# Set the title of the window
root.title('Calculator')
# Change the geometry of the window
root.geometry('300x450+750+150')
# Setting Minimum and Maximum window width and height
root.minsize(width=300, height=450)
root.maxsize(width=300, height=450)
# Create Rows and Columns to display widgets
root.rowconfigure(0, weight=100)
root.rowconfigure(1, weight=100)
root.rowconfigure(2, weight=100)
# Columns start here:
root.columnconfigure(0, weight=100)
root.columnconfigure(1, weight=100)
root.columnconfigure(2, weight=100)
# Configuring the Main window named: root
root.configure(bg='#353535')
# Creating the main label that will display the calculated results
lab_1 = tk.Label(root, width=40)
lab_1.grid(row=0, column=1, columnspan=1, sticky='we')
lab_1.configure(bg='#545454', font=('Computer Modern', 25, 'bold'),
                fg='White', justify='right')
# Main Calculator Layout
# List Box for a calculator layout
box_1 = tk.Listbox(root)
box_1.grid(row=1, column=1, rowspan=2)
box_1.configure(bg='#353535', relief='flat')
# Button Layout
calculator_layout = [[(7, 1), (8, 1), (9, 1), ('(', 1), (')', 1)],
                     [(4, 1), (5, 1), (6, 1), ('×', 1), ('÷', 1)],
                     [(1, 1), (2, 1), (3, 1), ('+', 1), ('-', 1)],
                     [(0, 1), ('±', 1), ('.', 1), ('-', 1), ('=', 1)]]

# Iterating through my list to get a set of buttons
row = 0
for i in calculator_layout:
    col = 0
    for a in i:
        key_press = tk.Button(box_1, text=a[0])
        key_press.grid(row=row, column=col, ipadx=10, ipady=8, sticky='we')
        key_press.configure(background='#545454', fg='white',
                            font=('Computer Modern', 10),
                            activebackground='red', state='normal')
        col += a[1]
    row += 1

root.mainloop()

你可以通过给出lambda each Button具有默认值的参数。不需要任何额外的for循环以这种方式执行（它是在创建Buttons).

下面显示了如何做到这一点# CHANGED评论。每个中的其余代码lambda函数定义的每个重新配置text的选项Label named lab_1通过调用其configure()方法并将其当前内容传递给text带有相关符号的选项Button附加到它。

...

# Iterating through my list to get a set of buttons
row = 0
for i in calculator_layout:
    col = 0
    for a in i:
        key_press = tk.Button(box_1, text=a[0])
        key_press.grid(row=row, column=col, ipadx=10, ipady=8, sticky='we')
        key_press.configure(background='#545454', fg='white',
                            font=('Computer Modern', 10),
                            activebackground='red', state='normal',
                            # CHANGED.
                            command=lambda sym=str(a[0]):
                                lab_1.configure(text=lab_1.cget('text')+sym))
        col += a[1]
    row += 1

root.mainloop()