使用 Python 请求的异步请求

我尝试了文档中提供的示例请求库对于蟒蛇。

With async.map(rs)，我得到了响应代码，但我想获取所请求的每个页面的内容。例如，这不起作用：

out = async.map(rs)
print out[0].content

Note

下面的答案是not适用于请求 v0.13.0+。异步功能已移至请求这个问题写完之后。但是，您可以只替换requests with grequests下面它应该可以工作。

我保留这个答案是为了反映关于使用 requests

执行多项任务async.map 异步地你必须：

1. 为您想要对每个对象执行的操作定义一个函数（您的任务）
2. 将该函数添加为请求中的事件挂钩
3. Call async.map在所有请求/操作的列表上

Example:

from requests import async
# If using requests > v0.13.0, use
# from grequests import async

urls = [
    'http://python-requests.org',
    'http://httpbin.org',
    'http://python-guide.org',
    'http://kennethreitz.com'
]

# A simple task to do to each response object
def do_something(response):
    print response.url

# A list to hold our things to do via async
async_list = []

for u in urls:
    # The "hooks = {..." part is where you define what you want to do
    # 
    # Note the lack of parentheses following do_something, this is
    # because the response will be used as the first argument automatically
    action_item = async.get(u, hooks = {'response' : do_something})

    # Add the task to our list of things to do via async
    async_list.append(action_item)

# Do our list of things to do via async
async.map(async_list)