我尝试使用以下代码片段设置 Spring Rest 模拟的上下文路径:
private MockMvc mockMvc;
@Before
public void setUp() {
this.mockMvc = MockMvcBuilders.webAppContextSetup(this.context)
.apply(documentationConfiguration(this.restDocumentation))
.alwaysDo(document("{method-name}/{step}/",
preprocessRequest(prettyPrint()),
preprocessResponse(prettyPrint())))
.build();
}
@Test
public void index() throws Exception {
this.mockMvc.perform(get("/").contextPath("/api").accept(MediaTypes.HAL_JSON))
.andExpect(status().isOk())
.andExpect(jsonPath("_links.business-cases", is(notNullValue())));
}
但我收到以下错误:
java.lang.IllegalArgumentException: requestURI [/] does not start with contextPath [/api]
怎么了?
是否可以在代码中的单个位置指定 contextPath,例如直接在构建器中?
edit
这里是控制器
@RestController
@RequestMapping(value = "/business-case", produces = MediaType.APPLICATION_JSON_VALUE)
public class BusinessCaseController {
private static final Logger LOG = LoggerFactory.getLogger(BusinessCaseController.class);
private final BusinessCaseService businessCaseService;
@Autowired
public BusinessCaseController(BusinessCaseService businessCaseService) {
this.businessCaseService = businessCaseService;
}
@Transactional(rollbackFor = Throwable.class, readOnly = true)
@RequestMapping(value = "/{businessCaseId}", method = RequestMethod.GET)
public BusinessCaseDTO getBusinessCase(@PathVariable("businessCaseId") Integer businessCaseId) {
LOG.info("GET business-case for " + businessCaseId);
return businessCaseService.findOne(businessCaseId);
}
}
您需要在要传递到的路径中包含上下文路径get
.
在您在问题中显示的情况下,上下文路径是/api
并且您想提出请求/
所以你需要通过/api/
to get
:
@Test
public void index() throws Exception {
this.mockMvc.perform(get("/api/").contextPath("/api").accept(MediaTypes.HAL_JSON))
.andExpect(status().isOk())
.andExpect(jsonPath("_links.business-cases", is(notNullValue())));
}
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)