我有一个 Django 单页应用程序。目前,当您访问网站上不存在的 URL 时,会显示 404 错误。但是,在这种情况下,我想重定向到该网站的主页。我不确定我是否应该如何使用 Nginx 执行此操作,或者是否有办法在 Django 中执行此操作?下面是我的 Nginx 文件。我尝试使用以下设置,但它不起作用。
error_page 404 = @foobar;
location @foobar {
return 301 /webapps/mysite/app/templates/index.html;
}
upstream mysite_wsgi_server {
# fail_timeout=0 means we always retry an upstream even if it failed
# to return a good HTTP response (in case the Unicorn master nukes a
# single worker for timing out).
server unix:/webapps/mysite/run/gunicorn.sock fail_timeout=0;
}
server {
listen 80;
server_name kanjisama.com;
rewrite ^ https://$server_name$request_uri? permanent;
}
server {
listen 443;
server_name kanjisama.com;
ssl on;
ssl_certificate /etc/letsencrypt/live/kanjisama.com/fullchain.pem;
ssl_certificate_key /etc/letsencrypt/live/kanjisama.com/privkey.pem;
ssl_protocols TLSv1 TLSv1.1 TLSv1.2;
client_max_body_size 4G;
access_log /webapps/mysite/logs/nginx_access.log;
error_log /webapps/mysite/logs/nginx_error.log;
location /static/ {
alias /webapps/mysite/app/static/;
}
location /media/ {
alias /webapps/mysite/media/;
}
location / {
if (-f /webapps/mysite/maintenance_on.html) {
return 503;
}
proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for;
proxy_set_header X-Forwarded-Proto https;
proxy_set_header Host $host;
proxy_redirect off;
# Try to serve static files from nginx, no point in making an
# *application* server like Unicorn/Rainbows! serve static files.
if (!-f $request_filename) {
proxy_pass http://mysite_wsgi_server;
break;
}
# Error pages
error_page 500 502 504 /500.html;
location = /500.html {
root /webapps/mysite/app/mysite/templates/;
}
error_page 503 /maintenance_on.html;
location = /maintenance_on.html {
root /webapps/mysite/;
}
error_page 404 = @foobar;
location @foobar {
return 301 /webapps/mysite/app/templates/index.html;
}
}
首先,创建一个视图来处理所有 404 请求。
# views.py
from django.shortcuts import redirect
def view_404(request, exception=None):
# make a redirect to homepage
# you can use the name of url or just the plain link
return redirect('/') # or redirect('name-of-index-url')
其次,将以下内容放入您的项目中urls.py
:
handler404 = 'myapp.views.view_404'
# replace `myapp` with your app's name where the above view is located
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)