这是一个创建 30x30 方格框的简单示例:
public static void main(String... args) throws IOException {
int w = 30, h = 30;
// create the binary mapping
byte BLACK = (byte)0, WHITE = (byte)255;
byte[] map = {BLACK, WHITE};
IndexColorModel icm = new IndexColorModel(1, map.length, map, map, map);
// create checkered data
int[] data = new int[w*h];
for(int i=0; i<w; i++)
for(int j=0; j<h; j++)
data[i*h + j] = i%4<2 && j%4<2 || i%4>=2 && j%4>=2 ? BLACK:WHITE;
// create image from color model and data
WritableRaster raster = icm.createCompatibleWritableRaster(w, h);
raster.setPixels(0, 0, w, h, data);
BufferedImage bi = new BufferedImage(icm, raster, false, null);
// output to a file
ImageIO.write(bi, "jpg", new File("C:\\Users\\user\\Desktop\\test.jpg"));
}
EDIT:
对于您正在做的事情,您实际上不需要创建自己的 ImageColorModel,您可以使用内置类型:BufferedImage.TYPE_BYTE_GRAY 或 TYPE_BYTE_BINARY。这是一个更好的示例,展示了如何使用灰度来获得方格框:
public static void main(String... args) throws IOException {
int w = 40, h = 40, divs = 5;
BufferedImage bi = new BufferedImage(w, h, BufferedImage.TYPE_BYTE_GRAY);
WritableRaster raster = bi.getRaster();
for(int i=0; i<w; i++)
for(int j=0; j<h; j++)
raster.setSample(i,j,0,128+(int)(127*Math.sin(Math.PI*i/w*divs)*Math.sin(Math.PI*j/h*divs)));
ImageIO.write(bi, "jpg", new File("C:\\Users\\user\\Desktop\\test.jpg"));
}