我似乎无法使用简单的正则表达式来工作。这是我目前所拥有的:
$(".Hours").on('input', function (e) {
var regex = /^\d+(\.\d{0,2})?$/g;
if (!regex.test(this.value)) {
if (!regex.test(this.value[0]))
this.value = this.value.substring(1, this.value.length);
else
this.value = this.value.substring(0, this.value.length - 1);
}
});
我需要用户只能输入数字和一位小数(小数点后只有两位数字)。它现在工作正常,但用户不能以小数开头。
可接受:
23.53
0.43
1111.43
54335.34
235.23
.53 <--- Not working
不可接受的:
0234.32 <--- The user can currently do this
23.453
1.343
.234.23
1.453.23
对此有什么帮助吗?
更新的答案:
RegExp -
^(?:0|[1-9]\d+|)?(?:.?\d{0,2})?$
解释于regex101:
原答案:
fiddle Demo
RegExp -
^(\d+)?([.]?\d{0,2})?$
解释
Assert position at the beginning of the string «^»
Match the regular expression below and capture its match into backreference number 1 «(\d+)?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match a single digit 0..9 «\d+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the regular expression below and capture its match into backreference number 2 «([.]?\d{0,2})?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match the character “.” «[.]?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match a single digit 0..9 «\d{0,2}»
Between zero and 2 times, as many times as possible, giving back as needed (greedy) «{0,2}»
Assert position at the end of the string (or before the line break at the end of the string, if any) «$»
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