In Log-in.php I have

  $email=$_POST['email']; 
  $pass=$_POST['pass'];
  $_SESSION['type'] = 'user';
  $_SESSION['email'] = $email; 
  $_SESSION['pass']=$pass; 
  header('location:./connect.php');

我收到类似的错误undefined index email对于其他用户登录，在另一边我可以在这里以管理员身份登录..

我有一个登录表单，可以查看这是什么类型的登录，并在会话中传递该类型连接.php它检查它是什么类型，然后继续它运行良好，但不幸的是出现错误无法再修改。

登录表单是用户、管理员和代理的一种表单，我可以以管理员身份登录，但无法以其他身份登录，它显示错误

if(empty($_SESSION))
{
   session_regenerate_id();
   session_start();
}
@mysql_connect('localhost','root','') or die("ERROR in SERVER");
@mysql_select_db('module') or die("ERROR IN DATABASE");

    $_SESSION['start'] = time(); // taking now logged in time

    if(!isset($_SESSION['expire'])){
        $_SESSION['expire'] = $_SESSION['start'] + (60* 60) ; // ending a session in 30 seconds
    }
    $now = time(); // checking the time now when home page starts

    if($now > $_SESSION['expire'])
    {
        session_destroy();

    }

if(!empty($_SESSION['type']))
{
$email = $_SESSION['email'];
$pass = $_SESSION['pass'];
$type = $_SESSION['type'];


// admin login //
if($type == 'admin'){




$admin = mysql_query("SELECT * FROM `admin` WHERE `email` ='$email' ");
$res = mysql_fetch_array($admin);
if($email == "" || $pass == "" || $email != $res['email'] || $pass != $res['pass'])
{
    header('location:./login/login.php');
}

}


// user login //
if($type == 'user')
{
     $email = $_SESSION['email'];
     $pass = $_SESSION['pass'];
     $type = $_SESSION['type'];
    $user = mysql_query("SELECT `id` FROM `users` WHERE `email`='$email' AND `status`='1'");
    $useres = mysql_fetch_array($user);
   // $trail = $useres['date'];
  //  $time = explode("/",$trail);


    if($email != $useres['email'] || $pass != $useres['pass'])

    {
        echo mysql_error();
//        header('location:./login/login.php');
    }

    else if($pass = $useres['pass']){
//        echo '<script> location.replace("./user.php"); </script>';
    }
}


// agent login //
if($type == 'agent')
{

    $email = $_SESSION['email'];
     $pass = $_SESSION['pass'];
     $type = $_SESSION['type'];
    $agent = mysql_query("SELECT `id` FROM `sale_agents` WHERE `email`='$email'");
    $agentres = mysql_fetch_array($agent);
    if($email != $agentres['email'] || $pass != $agentres['pass'])
    {
        header('location:./login/login.php');

    }
    else if($pass = $agentres['pass']){
   //     echo '<script> location.replace("./agent.php"); </script>';
    }
}
}
else{
    header('location:./login/login.php');
}

In one way I am getting error in other way page is also displaying email what to do now?

分步会议

1. 在一切之前定义会话，在此之前不应该有任何输出，无输出

   <?php
   session_start();
   ?>
   

2. 在页面中设置您的会话，然后您就可以访问该页面，例如这是第1页.php

   <?php
      //This is page 1 and then we will use session that defined from this page:
       session_start();
       $_SESSION['email]='[email protected]';
   ?>
   

3. 使用和获取会话2.php

    <?php
      //In this page I am going to use session:
     session_start();
     if($_SESSION['email']){
     echo 'Your Email Is Here!  :) ';
     }
    ?>
   

NOTE: 评论没有输出。

也许可以回答你的问题：

我认为你没有设置会话，因此 PHP 不知道该会话多变的。

你的登录应该是这样的

  <?php
  session_start();
  $email=$_POST['email']; 
  $pass=$_POST['pass'];
  $_SESSION['type'] = 'user';
  $_SESSION['email'] = $email; 
  $_SESSION['pass']=$pass; 
  header('location:./connect.php');
  ?>