类型错误：__init__() 需要 3 个位置参数，但给出了 4 个

这些是我的课程的代码：

class Employee:
    def __init__(self, name, gender):
        self.name = name
        self.gender = gender

class Salary:
    def jump(self, name, salary):
        print(self.name, self.salary)


class Male(Salary, Employee):
    def __init__(self, name, gender, occupation):
        super(Male, self).__init__(name, gender, occupation)
        self.occupation = occupation

# Separate from all classes (list of instantiated objects)
employee1 = Male("Jim", "male", "technician")
print(Male.name)

当我在创建所有类后使用代码的最后两行时，TypeError: __init__() takes 3 positional arguments but 4 were given引用时发生错误super(Male, self).... and employee1 = Male(... 线条。

在“宠物”下您有：

def __init__(self, name, color):
    self.name = name
    self.color = color

失败者你有：

def __init__(self, name, color, owner):
    super(Dog, self).__init__(name, color, owner)

在 Dog 下，给出了额外的所有者位置参数，这会导致此错误。顺便说一句，我认为super().__init__(name, color)在 Python 3 中也同样有效