每日一题：Alice的德州扑克

Alice的德州扑克 - 题目 - Daimayuan Online Judge

 从最大的牌开始判断，如果满足直接输出，return 0,否则就接着判断，一层一层往下判断

 AC代码：

#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int N = 20;
int a[N];
int color[N];
int cnt[N];
bool flaga;
bool flagcolor;
int main()
{
    flaga = true;
    flagcolor = true;
    for (int i = 1; i <= 5; i++) cin >> a[i];
    for (int i = 1; i <= 5; i++) cin >> color[i];
    for (int i = 2; i <= 5; i++) {
        if (a[i] != a[i - 1]+1) flaga = false;
    }
    sort(color+1, color+1 + 5);
    for (int i = 2; i <= 5; i++) {
        if (color[i] != color[i - 1]) flagcolor = false;
    }
    //flaga为true表示点数连续单调递增
    //flagcolor为true表示五张牌的花色相同
    if (flaga && flagcolor) {
        if (a[5] == 14) {
            cout << "ROYAL FLUSH" << endl;
            return 0;
        }
        else {
            cout << "STRAIGHT FLUSH" << endl;
            return 0;
        }
    }
    //用双指针求最大连续相同点数的个数
    int len=0;
    int j = 1;
    for (int i = 1; i <=5; i++) {
        while (j <= 5 && a[i] == a[j]) j++;
        len = max(len, j - i);
    }
    if (len >= 4) {
        cout << "FOUR OF A KIND" << endl;
        return 0;
    }
    //若len为3并且除此之外还有两张牌的点数相同，那么只有两种情况
    if (len == 3) {
        if (a[1] == a[2] && a[3] == a[4]&&a[4]==a[5] || a[1] == a[2]&&a[2]==a[3] && a[4] == a[5]) {
            cout << "FULL HOUSE" << endl;
            return 0;
        }
    }
    if (flagcolor) {
        cout << "FLUSH" << endl;
        return 0;
    }
    if (flaga) {
        cout << "STRAIGHT" << endl;
        return 0;
    }
    cout << "FOLD" << endl;
    return 0;
}