将2个已知有序的数组合并为一个新的有序数组。已有两个数组 arr1 和 arr2,要求将两个数组中元素合并到数组 arr3 中,合并时要去除数组中的重复数据。
#include <stdio.h>
int main(void)
{
int arr1[] = { 3,6,8,9,9,11,45 };
int arr2[] = { 1,3,6,8,45,89 };
int arr3[100];
int i, len;
int j, k, a, b;
int len1 = sizeof(arr1) / sizeof(arr1[0]);
int len2 = sizeof(arr2) / sizeof(arr2[0]);
len = len1 + len2;
for (i = 0; i < len1; i++) {
for (j = 0; j < len2; j++){
arr3[i] = arr1[i];
arr3[len1 + j] = arr2[j];
}
}
for (i = 0; i < len; i++){
for (j = i + 1; j < len; j++)
if (arr3[i] == arr3[j]){
for (k = j + 1; k < len; k++)
arr3[j] = arr3[k];
len--;
i--;
}
}
for (a = 0; a < len; a++) {
for (b = 0; b < len - a; b++) {
if (arr3[b] > arr3[b + 1]) {
k = arr3[b];
arr3[b] = arr3[b + 1];
arr3[b + 1] = k;
}
}
}
for (i = 0; i < len; ++i){
printf("%d ", arr3[i]);
}
printf("\n");
return 0;
}