SVPWM相电压幅值:
V
p
h
1
=
V
m
a
x
/
(
3
/
2
)
=
2
3
∗
U
d
c
∗
3
2
=
3
3
U
d
c
V_{ph1}=V_{max} / (\sqrt{ 3}/2) = {\frac 2 3} * U_{dc} * \frac {\sqrt{ 3}} 2 = {\frac {\sqrt{ 3}} 3} U_{dc}
Vph1=Vmax/(3/2)=32∗Udc∗23=33Udc SVPWM最大不失真相电压最大值:
V
p
h
=
2
3
U
d
c
∗
3
2
=
3
3
U
d
c
(
P
S
:
对
应
正
六
边
形
内
切
圆
)
V_{ph} = {\frac 2 3}U_{dc}* \frac {\sqrt{ 3}} 2 = { \frac {\sqrt{ 3}} 3}U_{dc}(PS:对应正六边形内切圆)
Vph=32Udc∗23=33Udc(PS:对应正六边形内切圆) SVPWM开关状态下相电压最大值:
2
3
U
d
c
(
P
S
:
对
应
6
个
基
本
电
压
电
压
矢
量
)
{\frac 2 3}U_{dc} (PS:对应6个基本电压电压矢量)
32Udc(PS:对应6个基本电压电压矢量) SPWM相电压幅值:
V
p
h
2
=
1
2
U
d
c
V_{ph2}= {\frac 1 2} U_{dc}
Vph2=21Udc SVPWM线电压幅值:
V
l
i
n
e
1
=
V
p
h
1
∗
3
=
2
3
∗
U
d
c
∗
3
2
∗
3
=
U
d
c
V_{line1}=V_{ph1}*\sqrt{ 3}= {\frac 2 3} * U_{dc} * {\frac {\sqrt{ 3}} 2} * \sqrt{ 3} = U_{dc}
Vline1=Vph1∗3=32∗Udc∗23∗3=Udc SPWM线电压幅值:
V
l
i
n
e
2
=
V
p
h
2
∗
3
=
3
2
U
d
c
V_{line2}=V_{ph2}*\sqrt{ 3} = {\frac {\sqrt{ 3}} 2} U_{dc}
Vline2=Vph2∗3=23Udc SVPWM输出最大直流母线电压利用率:
V
l
i
n
e
V
d
c
=
1
\frac {V_{line}} {V_{dc}} = 1
VdcVline=1 三相SPWM输出最大直流母线电压利用率:
3
2
U
d
c
U
d
c
=
3
2
≈
0.866
\frac {{\frac {\sqrt{ 3}} 2} U_{dc} } {U_{dc}} = {\frac {\sqrt{ 3}} 2} \approx 0.866
Udc23Udc=23≈0.866 SVPWM比SPWM直流电压利用率高:
1
3
2
≈
1.1547
\frac 1 {\frac {\sqrt{ 3}} 2} \approx 1.1547
231≈1.1547