如何使用正则表达式将字符串分成相同字符的组？

我有一个这样的字符串：

var string = "AAAAAAABBBCCCCCCDD"

并喜欢将字符串分割成这种格式的数组（same characters --> same group) 使用正则表达式:

Array: "AAAAAAA", "BBB", "CCCCCC", "DD"

这是我到目前为止所得到的，但说实话我无法真正让它发挥作用。

var array = [String]()
var string = "AAAAAAABBBCCCCCCDD"
let pattern = "\\ b([1,][a-z])\\" // mistake?!
let regex = try! NSRegularExpression(pattern: pattern, options: [])

array = regex.matchesInString(string, options: [], range: NSRange(location: 0, length: string.count))

您可以使用此功能来实现这一点answer https://stackoverflow.com/a/27880748/4763963:

func matches(for regex: String, in text: String) -> [String] {

    do {
        let regex = try NSRegularExpression(pattern: regex)
        let results = regex.matches(in: text,
                                    range: NSRange(text.startIndex..., in: text))
        return results.map {
            String(text[Range($0.range, in: text)!])
        }
    } catch let error {
        print("invalid regex: \(error.localizedDescription)")
        return []
    }
}

Passing (.)\\1+ as regex and AAAAAAABBBCCCCCCDD as text像这样：

let result = matches(for: "(.)\\1+", in: "AAAAAAABBBCCCCCCDD")
print(result) // ["AAAAAAA", "BBB", "CCCCCC", "DD"]