维基百科中的霍夫曼算法准确地告诉您如何创建节点树,因此您的程序可以基于该算法或其他类似算法。这是一个带有注释的 Python 程序,显示了相应的维基百科算法步骤。测试数据是英文文本中字母表字母的频率。
创建节点树后,您需要遍历它以将霍夫曼代码分配给数据集中的每个符号。由于这是家庭作业,因此这一步取决于您,但递归算法是处理它的最简单、最自然的方法。只剩下六行代码了。
import queue
class HuffmanNode(object):
def __init__(self, left=None, right=None, root=None):
self.left = left
self.right = right
self.root = root # Why? Not needed for anything.
def children(self):
return((self.left, self.right))
freq = [
(8.167, 'a'), (1.492, 'b'), (2.782, 'c'), (4.253, 'd'),
(12.702, 'e'),(2.228, 'f'), (2.015, 'g'), (6.094, 'h'),
(6.966, 'i'), (0.153, 'j'), (0.747, 'k'), (4.025, 'l'),
(2.406, 'm'), (6.749, 'n'), (7.507, 'o'), (1.929, 'p'),
(0.095, 'q'), (5.987, 'r'), (6.327, 's'), (9.056, 't'),
(2.758, 'u'), (1.037, 'v'), (2.365, 'w'), (0.150, 'x'),
(1.974, 'y'), (0.074, 'z') ]
def create_tree(frequencies):
p = queue.PriorityQueue()
for value in frequencies: # 1. Create a leaf node for each symbol
p.put(value) # and add it to the priority queue
while p.qsize() > 1: # 2. While there is more than one node
l, r = p.get(), p.get() # 2a. remove two highest nodes
node = HuffmanNode(l, r) # 2b. create internal node with children
p.put((l[0]+r[0], node)) # 2c. add new node to queue
return p.get() # 3. tree is complete - return root node
node = create_tree(freq)
print(node)
# Recursively walk the tree down to the leaves,
# assigning a code value to each symbol
def walk_tree(node, prefix="", code={}):
return(code)
code = walk_tree(node)
for i in sorted(freq, reverse=True):
print(i[1], '{:6.2f}'.format(i[0]), code[i[1]])
当对字母表数据运行时,生成的霍夫曼代码为:
e 12.70 100
t 9.06 000
a 8.17 1110
o 7.51 1101
i 6.97 1011
n 6.75 1010
s 6.33 0111
h 6.09 0110
r 5.99 0101
d 4.25 11111
l 4.03 11110
c 2.78 01001
u 2.76 01000
m 2.41 00111
w 2.37 00110
f 2.23 00100
g 2.02 110011
y 1.97 110010
p 1.93 110001
b 1.49 110000
v 1.04 001010
k 0.75 0010111
j 0.15 001011011
x 0.15 001011010
q 0.10 001011001
z 0.07 001011000