我在 stackoverflow 中使用 pandas 看到了很多 json 读取问题，但我仍然无法解决这个简单的问题。

Data

{"session_id":{"0":["X061RFWB06K9V"],"1":["5AZ2X2A9BHH5U"]},"unix_timestamp":{"0":[1442503708],"1":[1441353991]},"cities":{"0":["New York NY, Newark NJ"],"1":["New York NY, Jersey City NJ, Philadelphia PA"]},"user":{"0":[[{"user_id":2024,"joining_date":"2015-03-22","country":"UK"}]],"1":[[{"user_id":2853,"joining_date":"2015-03-28","country":"DE"}]]}}

我的尝试

import numpy as np
import pandas as pd
import json
from pandas.io.json import json_normalize

# attempt1
df = pd.read_json('a.json')

# attempt2
with open('a.json') as fi:
    data = json.load(fi)
    df = json_normalize(data,record_path='user',meta=['session_id','unix_timestamp','cities'])

Both of them do not give me the required output.

所需输出

      session_id unix_timestamp       cities  user_id joining_date country 
0  X061RFWB06K9V     1442503708  New York NY     2024   2015-03-22      UK   
0  X061RFWB06K9V     1442503708    Newark NJ     2024   2015-03-22      UK 

首选方法

https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.io.json.json_normalize.html https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.io.json.json_normalize.html

I would love to see implementation of pd.io.json.json_normalize

pandas.io.json.json_normalize(data: Union[Dict, List[Dict]], record_path: Union[str, List, NoneType] = None, meta: Union[str, List, NoneType] = None, meta_prefix: Union[str, NoneType] = None, record_prefix: Union[str, NoneType] = None, errors: Union[str, NoneType] = 'raise', sep: str = '.', max_level: Union[int, NoneType] = None)

相关链接

• Pandas 将字典列表分解为行 https://stackoverflow.com/questions/47148683/pandas-explode-list-of-dictionaries-into-rows/47149275
• 如何通过 Python Pandas 正确规范 json https://stackoverflow.com/questions/46091362/how-to-normalize-json-correctly-by-python-pandas
• JSON 到 pandas DataFrame https://stackoverflow.com/questions/21104592/json-to-pandas-dataframe

这是另一种方法：

df = pd.read_json(r'C:\path\file.json')

final=df.stack().str[0].unstack()
final=final.assign(cities=final['cities'].str.split(',')).explode('cities')
final=final.assign(**pd.DataFrame(final.pop('user').str[0].tolist()))
print(final)

      session_id unix_timestamp            cities  user_id joining_date  \
0  X061RFWB06K9V     1442503708       New York NY     2024   2015-03-22   
0  X061RFWB06K9V     1442503708         Newark NJ     2024   2015-03-22   
1  5AZ2X2A9BHH5U     1441353991       New York NY     2024   2015-03-22   
1  5AZ2X2A9BHH5U     1441353991    Jersey City NJ     2024   2015-03-22   
1  5AZ2X2A9BHH5U     1441353991   Philadelphia PA     2024   2015-03-22   

  country  
0      UK  
0      UK  
1      UK  
1      UK  
1      UK