ElasticSearch 映射对分组文档进行折叠/执行操作的结果

有一个对话列表，每个对话都有一个消息列表。每条消息都有不同的字段和action场地。我们需要考虑到在对话的第一条消息中使用了动作A，在几条消息之后有使用的动作A.1过了一会儿A.1.1等等（有一个聊天机器人意图列表）。

对对话的消息操作进行分组将类似于：A > A > A > A.1 > A > A.1 > A.1.1 ...

Problem:

我需要使用 ElasticSearch 创建一个报告，该报告将返回actions group每一次谈话；接下来，我需要将相似的分组actions groups添加计数；最终会导致Map<actionsGroup, count> as 'A > A.1 > A > A.1 > A.1.1', 3.

构建actions group我需要消除每组重复项；代替A > A > A > A.1 > A > A.1 > A.1.1我需要有A > A.1 > A > A.1 > A.1.1.

我开始做的步骤:

{
   "collapse":{
      "field":"context.conversationId",
      "inner_hits":{
         "name":"logs",
         "size": 10000,
         "sort":[
            {
               "@timestamp":"asc"
            }
         ]
      }
   },
   "aggs":{
   },
}

接下来我需要什么：

1. 我需要将崩溃的结果映射到单个结果中，例如A > A.1 > A > A.1 > A.1.1。我在案例中看到过这一点aggr可以使用scripts https://www.elastic.co/guide/en/elasticsearch/reference/current/search-aggregations-metrics-scripted-metric-aggregation.html根据结果​​，可以创建一个像我需要的操作列表，但是aggr正在对所有消息进行操作，而不仅仅是对我崩溃的分组消息进行操作。是否可以使用aggr内部崩溃或类似的解决方案？
2. 我需要对结果值进行分组（A > A.1 > A > A.1 > A.1.1）从所有崩溃中添加一个计数并得到Map<actionsGroup, count>.

Or:

1. 对对话消息进行分组conversationId现场使用aggr（我不知道我该怎么做）
2. 使用脚本迭代所有值并创建actions group对于每一次对话。 （不确定这是否可能）
3. 使用另一个aggr对所有值并对重复项进行分组，返回Map<actionsGroup, count>.

映射：

"mappings":{
  "properties":{
     "@timestamp":{
        "type":"date",
        "format": "epoch_millis"
     }
     "context":{
        "properties":{
           "action":{
              "type":"keyword"
           },
           "conversationId":{
              "type":"keyword"
           }
        }
     }
  }
}

对话的样本文件：

Conversation 1.
{
    "@timestamp": 1579632745000,
    "context": {
        "action": "A",
        "conversationId": "conv_id1",
    }
},
{
    "@timestamp": 1579632745001,
    "context": {
        "action": "A.1",
        "conversationId": "conv_id1",
    }
},
{
    "@timestamp": 1579632745002,
    "context": {
        "action": "A.1.1",
        "conversationId": "conv_id1",
    }
}

Conversation 2.
{
    "@timestamp": 1579632745000,
    "context": {
        "action": "A",
        "conversationId": "conv_id2",
    }
},
{
    "@timestamp": 1579632745001,
    "context": {
        "action": "A.1",
        "conversationId": "conv_id2",
    }
},
{
    "@timestamp": 1579632745002,
    "context": {
        "action": "A.1.1",
        "conversationId": "conv_id2",
    }
}

Conversation 3.
{
    "@timestamp": 1579632745000,
    "context": {
        "action": "B",
        "conversationId": "conv_id3",
    }
},
{
    "@timestamp": 1579632745001,
    "context": {
        "action": "B.1",
        "conversationId": "conv_id3",
    }
}

预期结果：

{
    "A -> A.1 -> A.1.1": 2,
    "B -> B.1": 1
}
Something similar, having this or any other format.

我用以下方法解决了这个问题scripted_metric的弹性。另外，index从初始状态发生了变化。

剧本：

{
   "size": 0,
   "aggs": {
        "intentPathsCountAgg": {
            "scripted_metric": {
                "init_script": "state.messagesList = new ArrayList();",
                "map_script": "long currentMessageTime = doc['messageReceivedEvent.context.timestamp'].value.millis; Map currentMessage = ['conversationId': doc['messageReceivedEvent.context.conversationId.keyword'], 'time': currentMessageTime, 'intentsPath': doc['brainQueryRequestEvent.brainQueryRequest.user_data.intentsHistoryPath.keyword'].value]; state.messagesList.add(currentMessage);",  
                "combine_script": "return state",
                "reduce_script": "List messages = new ArrayList(); Map conversationsMap = new HashMap(); Map intentsMap = new HashMap(); String[] ifElseWorkaround = new String[1]; for (state in states) { messages.addAll(state.messagesList);} messages.stream().forEach((message) -> { Map existingMessage = conversationsMap.get(message.conversationId); if(existingMessage == null || message.time > existingMessage.time) { conversationsMap.put(message.conversationId, ['time': message.time, 'intentsPath': message.intentsPath]); } else { ifElseWorkaround[0] = ''; } }); conversationsMap.entrySet().forEach(conversation -> { if (intentsMap.containsKey(conversation.getValue().intentsPath)) { long intentsCount = intentsMap.get(conversation.getValue().intentsPath) + 1; intentsMap.put(conversation.getValue().intentsPath, intentsCount); } else {intentsMap.put(conversation.getValue().intentsPath, 1L);} }); return intentsMap.entrySet().stream().map(intentPath -> [intentPath.getKey().toString(): intentPath.getValue()]).collect(Collectors.toSet()) "
            }
        }
    }
}

格式化脚本（为了更好的可读性 - 使用 .ts）：

scripted_metric: {
  init_script: 'state.messagesList = new ArrayList();',
  map_script: `
    long currentMessageTime = doc['messageReceivedEvent.context.timestamp'].value.millis;
    Map currentMessage = [
      'conversationId': doc['messageReceivedEvent.context.conversationId.keyword'],
      'time': currentMessageTime,
      'intentsPath': doc['brainQueryRequestEvent.brainQueryRequest.user_data.intentsHistoryPath.keyword'].value
    ];
    state.messagesList.add(currentMessage);`,
  combine_script: 'return state',
  reduce_script: `
    List messages = new ArrayList();
    Map conversationsMap = new HashMap();
    Map intentsMap = new HashMap();
    boolean[] ifElseWorkaround = new boolean[1];

    for (state in states) {
      messages.addAll(state.messagesList);
    }

    messages.stream().forEach(message -> {
      Map existingMessage = conversationsMap.get(message.conversationId);
      if(existingMessage == null || message.time > existingMessage.time) {
        conversationsMap.put(message.conversationId, ['time': message.time, 'intentsPath': message.intentsPath]);
      } else {
        ifElseWorkaround[0] = true;
      }
    });

    conversationsMap.entrySet().forEach(conversation -> {
      if (intentsMap.containsKey(conversation.getValue().intentsPath)) {
        long intentsCount = intentsMap.get(conversation.getValue().intentsPath) + 1;
        intentsMap.put(conversation.getValue().intentsPath, intentsCount);
      } else {
        intentsMap.put(conversation.getValue().intentsPath, 1L);
      }
    });

    return intentsMap.entrySet().stream().map(intentPath -> [
      'path': intentPath.getKey().toString(),
      'count': intentPath.getValue()
    ]).collect(Collectors.toSet())`

答案：

{
    "took": 2,
    "timed_out": false,
    "_shards": {
        "total": 5,
        "successful": 5,
        "skipped": 0,
        "failed": 0
    },
    "hits": {
        "total": {
            "value": 11,
            "relation": "eq"
        },
        "max_score": null,
        "hits": []
    },
    "aggregations": {
        "intentPathsCountAgg": {
            "value": [
                {
                    "smallTalk.greet -> smallTalk.greet2 -> smallTalk.greet3": 2
                },
                {
                    "smallTalk.greet -> smallTalk.greet2 -> smallTalk.greet3  -> smallTalk.greet4": 1
                },
                {
                    "smallTalk.greet -> smallTalk.greet2": 1
                }
            ]
        }
    }
}