VideoCamera 获取支持的分辨率

我使用 DirectShow 库 (DirectShowLib-2005.dll) 和 C# 来捕获摄像机图像。当我定义捕获对象的大小时，我有以下参数：

const int VIDEOWIDTH = 640; // Depends on video device caps
const int VIDEOHEIGHT = 480; // Depends on video device caps
const int VIDEOBITSPERPIXEL = 24; // BitsPerPixel values determined by device

capture = new Capture(0, VIDEOWIDTH, VIDEOHEIGHT, VIDEOBITSPERPIXEL, pictureBox1);

我正在使用此循环来获取设备名称。我可以以某种方式读取每个摄像头的所有可能的分辨率吗？

DsDevice[] capDevices;
capDevices = DsDevice.GetDevicesOfCat(FilterCategory.VideoInputDevice);
if (capDevices.Length == 0)
{
  //Could not found camera
}
else
{
  for (var i = 0; i < capDevices.Length; i++)
  {
    myCamerName = capDevices[i].Name.ToString();
  }
} 

在网上搜索终于找到了一个代码片段，使用IPin.EnumMediaTypes

private List<string> GetAllAvailableResolution(DsDevice vidDev)
{
   try
   {
     int hr, bitCount = 0;

     IBaseFilter sourceFilter = null;

     var m_FilterGraph2 = new FilterGraph() as IFilterGraph2;
     hr = m_FilterGraph2.AddSourceFilterForMoniker(vidDev.Mon, null, vidDev.Name, out sourceFilter);
     var pRaw2 = DsFindPin.ByCategory(sourceFilter, PinCategory.Capture, 0);
     var AvailableResolutions = new List<string>();

     VideoInfoHeader v = new VideoInfoHeader();
     IEnumMediaTypes mediaTypeEnum;
     hr = pRaw2.EnumMediaTypes(out mediaTypeEnum);

     AMMediaType[] mediaTypes = new AMMediaType[1];
     IntPtr fetched = IntPtr.Zero;
     hr = mediaTypeEnum.Next(1, mediaTypes, fetched);

     while (fetched != null && mediaTypes[0] != null)
     {
       Marshal.PtrToStructure(mediaTypes[0].formatPtr, v);
       if (v.BmiHeader.Size != 0 && v.BmiHeader.BitCount != 0)
       {
         if (v.BmiHeader.BitCount > bitCount)
         {
           AvailableResolutions.Clear();
           bitCount = v.BmiHeader.BitCount;
         }
         AvailableResolutions.Add(v.BmiHeader.Width +"x"+ v.BmiHeader.Height);
       }
       hr = mediaTypeEnum.Next(1, mediaTypes, fetched);
     }
     return AvailableResolutions;
   }
   catch (Exception ex)
   {
     MessageBox.Show(ex.Message);
     return new List<string>();
   }
}