我应该将 onClickListener 放在自定义 ListView 的哪里？

我正在定制ListView包含 a 的行数CheckBox and a TextView。在我使用自定义之前ListViews使用 SimpleCursorAdapter，我的onListItemClick()工作得很好。

我读过我必须添加一个onClickListener to my TextViews但是哪里？为什么？

我还在延长ListActivity并通过一个Adapter to setListAdapter(listedPuzzleAdapter);，我不是吗？

public class PuzzleListActivity extends ListActivity {

    private PuzzlesDbAdapter mDbHelper;
    private Cursor puzzlesCursor;

    private ArrayList<ListedPuzzle> listedPuzzles = null;
    private ListedPuzzleAdapter listedPuzzleAdapter;

    private class ListedPuzzleAdapter extends ArrayAdapter<ListedPuzzle> {

        private ArrayList<ListedPuzzle> items;

        public ListedPuzzleAdapter(Context context, int textViewResourceId,
                ArrayList<ListedPuzzle> items) {
            super(context, textViewResourceId, items);
            this.items = items;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            View v = convertView;
            if (v == null) {
                LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                v = vi.inflate(R.layout.puzzles_row, null);
            }
            ListedPuzzle lp = items.get(position);
            if (lp != null) {
                TextView title = (TextView) v.findViewById(R.id.listTitles);
                title.setText(lp.getTitle());
                CheckBox star = (CheckBox) v.findViewById(R.id.star_listed);
                star.setChecked(lp.isStarred());
            }
            return v;
        }

    }

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState); 

        setContentView(R.layout.puzzles_list);

        // Create database helper to open connection
        mDbHelper = new PuzzlesDbAdapter(this);
        mDbHelper.open();

        fetchData();
    }   

    private void fetchData() {
        puzzlesCursor = mDbHelper.fetchAllPuzzles();
        startManagingCursor(puzzlesCursor);

        listedPuzzles = new ArrayList<ListedPuzzle>();
        ListedPuzzle lp;

        puzzlesCursor.moveToFirst();
        while (!puzzlesCursor.isAfterLast()) {
            lp = new ListedPuzzle();
            lp.setTitle(puzzlesCursor.getString(puzzlesCursor
                    .getColumnIndex(PuzzlesDbAdapter.KEY_TITLE)));
            lp.setStarred(puzzlesCursor.getInt(puzzlesCursor
                    .getColumnIndex(PuzzlesDbAdapter.KEY_STARRED)) > 0);
            listedPuzzles.add(lp);
            puzzlesCursor.moveToNext();
        }

        listedPuzzleAdapter = new ListedPuzzleAdapter(this,
                R.layout.puzzles_row, listedPuzzles);
        setListAdapter(listedPuzzleAdapter);

    }

    @Override
    protected void onListItemClick(ListView l, View v, int position, long id) {
        super.onListItemClick(l, v, position, id);
        Intent i = new Intent(this, PuzzleQuestionActivity.class);
        i.putExtra(PuzzlesDbAdapter.KEY_ROWID, id);
        startActivity(i);
    }

编辑：我的问题是制作整个定制项目ListView可点击，所以我发现最好的答案是@Luksprog 给出的答案。这onListItemClick从我的ListActivity就足够了。我只需要设置android:focusable='false'使其发挥作用。

现在CheckBox的每一项上ListView应该“星号”该项目，这意味着访问数据库。

public View getView(int position, View convertView, ViewGroup parent) {
            View v = convertView;
            if (v == null) {
                LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                v = vi.inflate(R.layout.puzzles_row, null);
            }
            ListedPuzzle lp = items.get(position);
            if (lp != null) {
                TextView title = (TextView) v.findViewById(R.id.listTitles);
                title.setText(lp.getTitle());
                CheckBox star = (CheckBox) v.findViewById(R.id.star_listed);
                star.setChecked(lp.isStarred());

                star.setOnCheckedChangeListener(new OnCheckedChangeListener() {

                    public void onCheckedChanged(CompoundButton buttonView,
                            boolean isChecked) {
                        Integer realPosition = (Integer) v.getTag();
                        ListedPuzzle obj = items.get(realPosition);
                        obj.getId();

                    }

                });
            }
            return v;

        }

But the v.getTag()指的是一个非最终变量，如果我改变它v = vi.inflate(R.layout.puzzles_row, null)无法分配。 解决这个问题的最佳方法是什么？我从来没有真正理解整个最终协议。

如果您想在单击时添加特殊操作TextView or/and CheckBox从你的任何行ListView然后添加一个OnCLickListener对于那些Views in the getView您定制的方法Adapter:

 @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            View v = convertView;
            if (v == null) {
                LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                v = vi.inflate(R.layout.puzzles_row, null);
            }
            ListedPuzzle lp = items.get(position);
            if (lp != null) {
                TextView title = (TextView) v.findViewById(R.id.listTitles);
                //set as the tag the position parameter 
                title.setTag(new Integer(position));                    
                title.setOnclickListener(new OnCLickListener(){

                @Override 
                public void onClick(View v) {
                    // Do the stuff you want for the case when the row TextView is clicked
                    // you may want to set as the tag for the TextView the position paremeter of the `getView` method and then retrieve it here
                    Integer realPosition = (Integer) v.getTag();
                    // using realPosition , now you know the row where this TextView was clicked
                }
            }); 
                title.setText(lp.getTitle());
                CheckBox star = (CheckBox) v.findViewById(R.id.star_listed);
                star.setChecked(lp.isStarred());
            }
            return v;
        }

如果您想在单击一行时执行操作（无论什么View从该行被点击（如果被点击））只需使用OnItemClickListener在你的ListView（或者回调onListItemClick如果是ListActivity).

另外，我希望你设置android:focusable="false"为了CheckBox(in R.layout.puzzles_row）因为我不认为onListItemClick否则会起作用。

Edit :

你开始新的Activity in the onListItemClick（在这种情况下ListActivity) 如果你想开始新的活动回调无论用户单击一行的何处:

@Override
    protected void onListItemClick(ListView l, View v, int position, long id) {          
        Intent i = new Intent(this, PuzzleQuestionActivity.class);
        i.putExtra(PuzzlesDbAdapter.KEY_ROWID, id);
        startActivity(i);
    }

如果由于某种原因您想开始新的Activity当用户点击时only（例如）TextView in a ListView行然后开始新的活动onClick我上面的代码中的方法：

//...
title.setOnclickListener(new OnCLickListener(){

                    @Override 
                    public void onClick(View v) {
                        Integer realPosition = (Integer) v.getTag();
                        ListedPuzzle obj = items.get(realPosition);
                        Intent i = new Intent(this, PuzzleQuestionActivity.class);
                        i.putExtra(PuzzlesDbAdapter.KEY_ROWID, obj.getTheId());//see below
                        startActivity(i);
                    }
//...

为此，您必须修改ListedPuzzle还要添加PuzzlesDbAdapter.KEY_ROWID列从puzzlesCursor光标在fetchData() method:

//...
while (!puzzlesCursor.isAfterLast()) {
            lp = new ListedPuzzle();
            lp.setTitle(puzzlesCursor.getString(puzzlesCursor
                    .getColumnIndex(PuzzlesDbAdapter.KEY_TITLE)));
            lp.setStarred(puzzlesCursor.getInt(puzzlesCursor
                    .getColumnIndex(PuzzlesDbAdapter.KEY_STARRED)) > 0);
            lp.setTheId(puzzlesCursor.getLong(puzzlesCursor
                    .getColumnIndex(PuzzlesDbAdapter.KEY_ROWID)));
            listedPuzzles.add(lp);
//...