这是我正在尝试做的事情,但没有成功。我想打电话from x in list1
and join y in list2 where regex.Match(x.Value).Success
。完成这些步骤后我需要打电话String.Replace
两次x.Value
。然后致电on
and select
运营商。我希望它看起来像第二个例子。如何才能实现这一目标?
我的列表如下所示:
list1 list2
Name Value Name Value
item.1 $(prod1) prod1 prodVal1
item.2 $(prod2) prod2 prodVal2
item.3 prod3 prod3 prodVal3
我的列表应该是这样的:
updatedList
Name Value
item.1 prodVal1
item.2 prodVal2
item.3 prod3
示例1(这是我目前拥有的):
foreach (var x in list1)
{
Match match = reg.Match(x.Value);
if (match.Success)
{
x.Value = x.Value.Replace("$(", "");
x.Value = x.Value.Replace(")", "");
}
}
var commonItems = from x in list1
join y in list2
on x.Value equals y.Name
//where regex.Match(x.Value).Success
select new { Item = x, NewValue = y.Value };
foreach (var x in commonItems)
{
x.Item.Value = x.NewValue;
}
示例2:
var commonItems = from x in list1
join y in list2
where regex.Match(x.Value).Success
//do x.Value.Replace("$(", "")
//do x.Value.Replace(")", "")
//then call
on x.Value equals y.Name
select new { Item = x, NewValue = y.Value };
foreach (var x in commonItems)
{
x.Item.Value = x.NewValue;
}
如果我理解正确的话你想要的是使用let
在您的查询中:
var commonItems = from x in list1
join y in list2
let newX = x.Value.Replace("$(", "").Replace(")", "")
where regex.Match(x.Value).Success
&& newX == y.Name
select new { Item = newX, NewValue = y.Value };
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