我有两个表：标准和服务产品。一个标准可以有多个服务产品。每个标准可以有不同数量的与其关联的服务产品。
我需要做的是编写一个视图，该视图将返回一些常见数据，然后在一行上列出服务产品。例如：
Standard Id | Description | SO #1 | SO #2 | SO #3 | ... | SO #21 | SO Count
1 | One | A | B | C | ... | G | 21
2 | Two | A | | | ... | | 1
3 | Three | B | D | E | ... | | 3
我不知道如何写这个。 SO 列的数量设置为特定数量（本例中为 21），因此我们不能超过该数量。
关于如何解决这个问题有什么想法吗？
我开始的地方如下。当每个服务产品需要位于一行时，它只是返回多行。
SELECT *
FROM SERVICE_OFFERINGS
WHERE STANDARD_KEY IN (SELECT STANDARD_KEY
FROM STANDARDS)
附加 SQL
这是我的 SQL，它返回我想要的所有内容，但由于有 11 个服务产品，因此将返回 11 行。我一直在尝试数据透视表，但似乎无法弄清楚这一点。有人可以帮忙提供一个代码示例吗？
SELECT DISTINCT stpc.standard_key,
stpc.test_id,
NULL AS pricebook_id,
stpc.stabdard_name AS description,
stpc.date_start AS begin_date,
stpc.date_end AS end_date,
sopd.service_offering_id
FROM STANDARDS stpc,
SERVICE_OFFERINGS sopd
WHERE 1=1
AND sopd.standard_key = stpc.standard_key
ORDER BY stpc.standard_key, sopd.service_offering_id
UPDATE
由于数据库不支持 PIVOT 表（并且无法找出 XML 建议），因此我必须执行一些棘手的 SQL 才能使其正常工作。这是我使用的：
select stpc.oracle_product_code AS test_id,
CASE WHEN stpc.store_key = 200 THEN 'CE_USAUSD09'
WHEN stpc.store_key = 210 THEN 'CE_CANCAD09' END AS pricebook_id,
stpc.standard_name AS its_test_desc,
CONVERT(VARCHAR(10), stpc.date_start, 101) AS begin_date,
CONVERT(VARCHAR(10), stpc.date_end, 101) AS end_date,
MAX(CASE WHEN rn = 1 THEN b.service_offering_id END) AS SERVICE_OFFERING_1,
MAX(CASE WHEN rn = 2 THEN b.service_offering_id END) AS SERVICE_OFFERING_2,
MAX(CASE WHEN rn = 3 THEN b.service_offering_id END) AS SERVICE_OFFERING_3,
MAX(CASE WHEN rn = 4 THEN b.service_offering_id END) AS SERVICE_OFFERING_4,
MAX(CASE WHEN rn = 5 THEN b.service_offering_id END) AS SERVICE_OFFERING_5,
MAX(CASE WHEN rn = 6 THEN b.service_offering_id END) AS SERVICE_OFFERING_6,
MAX(CASE WHEN rn = 7 THEN b.service_offering_id END) AS SERVICE_OFFERING_7,
MAX(CASE WHEN rn = 8 THEN b.service_offering_id END) AS SERVICE_OFFERING_8,
MAX(CASE WHEN rn = 9 THEN b.service_offering_id END) AS SERVICE_OFFERING_9,
MAX(CASE WHEN rn = 10 THEN b.service_offering_id END) AS SERVICE_OFFERING_10,
MAX(CASE WHEN rn = 11 THEN b.service_offering_id END) AS SERVICE_OFFERING_11,
MAX(CASE WHEN rn = 12 THEN b.service_offering_id END) AS SERVICE_OFFERING_12,
MAX(CASE WHEN rn = 13 THEN b.service_offering_id END) AS SERVICE_OFFERING_13,
MAX(CASE WHEN rn = 14 THEN b.service_offering_id END) AS SERVICE_OFFERING_14,
MAX(CASE WHEN rn = 15 THEN b.service_offering_id END) AS SERVICE_OFFERING_15,
MAX(CASE WHEN rn = 16 THEN b.service_offering_id END) AS SERVICE_OFFERING_16,
MAX(CASE WHEN rn = 17 THEN b.service_offering_id END) AS SERVICE_OFFERING_17,
MAX(CASE WHEN rn = 18 THEN b.service_offering_id END) AS SERVICE_OFFERING_18,
MAX(CASE WHEN rn = 19 THEN b.service_offering_id END) AS SERVICE_OFFERING_19,
MAX(CASE WHEN rn = 20 THEN b.service_offering_id END) AS SERVICE_OFFERING_20,
MAX(CASE WHEN rn = 21 THEN b.service_offering_id END) AS SERVICE_OFFERING_21,
MAX(rn) AS service_offering_count
FROM (
select standard_key,
service_offering_id,
row_number() over (partition by standard_key order by standard_key) rn
from SERVICE_OFFERINGS
) B,
SERVICE_OFFERINGS sopd,
STANDARDS stpc
where b.service_offering_id = sopd.service_offering_id
AND b.standard_key = stpc.standard_key
AND sopd.standard_key = stpc.standard_key
AND stpc.store_key IN (200,210)
AND stpc.create_date > '03/29/2010'
group by stpc.oracle_product_code,stpc.store_key,stpc.standard_name,stpc.date_start,stpc.date_end
