我必须使用 REST Web 服务中的接口。这是接口 Specs.java :
@XmlJavaTypeAdapter(MyAdapter.class)
public interface Specs {
public BaseProperties getBaseProps();
public void setBaseProps(BaseProperties baseProps);
}
MyAdapter.java:
public class MyAdapter extends XmlAdapter<Object,Object>
{
public Object unmarshal(Object v)
{
return v;
}
public Object marshal(Object v)
{
return v;
}
}
RegSpecs.java
@XmlType
public class RegSpecs implements Specs{
private BaseProperties baseProps;
public BaseProperties getBaseProps()
{
return baseProps;
}
public void setBaseProps(BaseProperties baseProps)
{
this.baseProps = baseProps;
}
}
MapSpecs.java
@XmlType
public class MagSpecs implements Specs {
private BaseProperties baseProps;
private Features features;
public BaseProperties getBaseProps()
{
return baseProps;
}
public void setBaseProps(BaseProperties baseProps)
{
this.baseProps = baseProps;
}
public Features getFeatures() {
return features;
}
public void setFeatures(Features features) {
this.features = features;
}
}
访问此服务会引发以下错误:
javax.xml.bind.MarshalException
- 带有链接异常:
[javax.xml.bind.JAXBException:类Entity.MagSpecs及其任何超类在此上下文中都是已知的。]
如何修改我的上下文?我正在使用与 Jersey 1.5 捆绑在一起的 JAXB
Thanks !
编辑:为了更新我的上下文,我将此代码添加到我的客户端(资源)类中:
public class BookService implements ContextResolver<JAXBContext>
{
private JAXBContext jaxbContext;
public BookService() {
try {
// Bootstrap your JAXBContext will all necessary classes
jaxbContext = JAXBContext.newInstance(Specs.class,MagSpecs.class, RegSpecs.class);
} catch(Exception e) {
throw new RuntimeException(e);
}
}
public JAXBContext getContext(Class<?> clazz) {
if(BookService.class == clazz) {
return jaxbContext;
}
return null;
}
在这种情况下我收到错误:
Entity.Specs 是一个接口,JAXB 无法处理接口。
该问题与以下位置有关:
在实体.规格
Entity.Specs 没有无参数默认构造函数。
该问题与以下位置有关:
在实体.规格