Java中交替显示2个字符串

我有一个java程序，其中我想要实现以下目标：

first input: ABC

second input: xyz

output: AxByCz

我的Java程序如下：

    import java.io.*;

    class DisplayStringAlternately 
    {
        public static void main(String[] arguments)
        {
            String firstC[], secondC[];

            firstC = new String[] {"A","B","C"};
            secondC = new String[] {"x","y","z"};

            displayStringAlternately(firstC, secondC);        
        }

        public static void displayStringAlternately (String[] firstString, String[] secondString)
        {
           int combinedLengthOfStrings = firstString.length + secondString.length;

           for(int counter = 1, i = 0; i < combinedLengthOfStrings; counter++, i++)
           {
               if(counter % 2 == 0)
               {
                   System.out.print(secondString[i]);
               }
               else 
               {
                   System.out.print(firstString[i]);
               }
           }
        }        
    }

但是我遇到以下运行时错误：

    Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 3
    AyC at DisplayStringAlternately.displayStringAlternately(DisplayStringAlternately.java:23)
        at DisplayStringAlternately.main(DisplayStringAlternately.java:12)
    Java Result: 1

我的 Java 程序出了什么错误？

如果两个数组的长度相同for循环应该继续 whilei < anyArray.length.

而且你不需要任何counter以确定您应该首先打印哪个数组。只需硬编码将打印的第一个元素firstString下一张来自secondString.

So your displayStringAlternately方法可以看起来像

public static void displayStringAlternately(String[] firstString,
        String[] secondString) {
    for (int i = 0; i < firstString.length; i++) {
        System.out.print(firstString[i]);
        System.out.print(secondString[i]);
    }
}

无论如何你的代码会抛出ArrayIndexOutOfBoundsException因为每次您决定从哪个数组打印元素递增i，所以你可以通过这种方式有效地跳过数组

 i=0     i=2
{"A","B","C"};

{"x","y","z"};    
     i=1     i=3 
             ^^^-here is the problem

因此，正如您所看到的，您的代码尝试访问第二个数组中不在其中的元素（它超出了其范围）。