不知道如何一次打印整个日历[关闭]

2024-04-22

cseg segment
assume cs:cseg, ds:cseg
org 100H
begin:   
                mov es,cs:[video]
                mov ax,3
                int 10h 
                mov cs:[col],0fh
                mov di,10               ;greeting msg will be printed after 10 spaces
                lea si,greeting
                call mess
                call nline        
                call jan
                call nline
                mov ah,4ch
                int 21h

col             db 0
greeting        db "Welcome to the 2015 Calendar ",0  
video           dw 0b800h
january         db  "         January$",     
string          db  "Sun Mon Tue Wed Thu Fri Sat$"
string1         db  "         1   2   3   4   5$"
string2         db  " 6   7   8   9  10  11  12$"
string3         db  "13  14  15  16  17  18  19$"
string4         db  "20  21  22  23  24  25  26$"
string5         db  "27  28  29  30  31$"

mess            proc
                push ax
                mov ah,cs:[col]
                mov bh, 30
conmess:
                mov al,cs:[si]
                or al,al
                jz endmess
                mov es:[di],ax  
                mov es:[di+1],bh
                inc si
                add di,2
                jmp conmess
endmess:
                pop ax
                ret
mess            endp

nline           proc
                mov ah, 2                    ; carriage return
                mov DL, 0DH
                int 21H    
                mov DL, 0AH                  ; line feed
                int 21H 
                ret
nline           endp   

print: 
                ;printing the line
                mov bh,10h  ;color attribute
                mov ah,9 
                mov al,0  ;avoding extra characters
                int 10h   ;printing color
                int 21h
                ret 

jan             proc 
                lea dx,january               ; load & display the STRIN
                call print
                call nline
                lea dx, string               ; load & display the STRING 
                call print
                call nline
                lea dx, string1              ; load & display the STRING 
                call print
                call nline
                lea DX, string2               ; load & display the STRING 
                call print
                call nline
                lea DX, string3               ; load & display the STRING 
                call print 
                call nline
                lea DX, string4               ; load & display the STRING 
                call print      
                call nline
                lea DX, string5               ; load & display the STRING 
                call print
                call nline 
                ret
jan             endp

cseg ends
end begin

assume cs:cseg, ds:cseg
org 100H

因为你用过org 100h我假设您正在编写 DOS'.COM 格式的可执行文件。

mov di,10               ;greeting msg will be printed after 10 spaces

要产生 10 个空格,您需要设置 DI=20,因为在 0B800h 的视频 RAM 中,每个字符占用 2 个字节。

mess  proc
  push ax
  mov ah,cs:[col]
  mov bh, 30         ; You don't need this line
 conmess:
  mov al,cs:[si]
  or al,al
  jz endmess
  mov es:[di],ax  
  mov es:[di+1],bh   ; You don't need this line
  inc si
  add di,2
  jmp conmess
 endmess:
  pop ax
  ret
mess  endp

通过直接写入视频RAM 来显示问候消息。为什么要插入两种方式来定义属性字节?

print:
 mov bh,10h  ; Delete this line
 mov ah,9 
 mov al,0    ; Delete this line
 int 10h     ; Delete this line
 int 21h
 ret

其余的编写是通过 DOS 函数完成的。这print例程似乎混合了 BIOS 和 DOS 功能!对于 DOS,你只需要 AH=9

mov ah,4ch
int 21h

Terminate 函数要求您在 AL 寄存器中定义退出代码。使用mov ax,4C00h.

而不是繁琐的调用nline要生成 CRLF,您可以轻松地将这两个字节写入要输出的字符串中。
就像这个例子

string2         db  " 6   7   8   9  10  11  12",13,10,"$"

大多数例程都是使用 PROC/ENDP 声明的,但是print不是。请选择一种系统并坚持使用。

EDIT

由于所有字符串都显示在单独的行上,为它们提供颜色的最简单的解决方案是使用所需的属性擦除当前行。以下是对第一个字符串执行此操作的方法

mov ax,0920h                    \
mov bx,001Eh  ;Yellow on Blue    | Best put this in a subroutine!
mov cx,80                        |
int 10h                         /
lea dx,january
call print
call nline
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