重复AlarmManager如何启动AsyncTask？

我通常编写这段代码来启动服务AlarmManager.

    intent = new Intent(getActivity(), someservice.class);
    pendingNotificationIntent = PendingIntent.getService(getActivity(), 0, intent, 0);
    alarm = (AlarmManager) getActivity().getSystemService(getActivity().ALARM_SERVICE);
    int interval = 30 * 1000;
    long now = Calendar.getInstance().getTimeInMillis();
    alarm.setRepeating(AlarmManager.RTC_WAKEUP, now, interval, pendingNotificationIntent);

My AsyncTask是我注册的私人课程AlarmManager目的。

我怎样才能打电话给AsyncTask而不是使用服务AlarmManager object?

附言。如果有更好的跑步方式AsyncTask每X秒/分钟，请提出！

根据慕尼黑卡托奇 https://stackoverflow.com/users/1751027/munish-katoch的回复，我有以下具体解决方案。

设置闹钟：

Intent intent = new Intent(context, AlarmReceiver.class);

PendingIntent alarmIntent = PendingIntent.getBroadcast(context, 0, intent, 0);

AlarmManager alarmMgr = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE);
alarmMgr.setInexactRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP, 
  SystemClock.elapsedRealtime() + 5 * 1000, 60 * 1000, alarmIntent);

上面的代码配置了AlarmManager向AlarmReceiver，其定义如下：

public class AlarmReceiver extends WakefulBroadcastReceiver {
  @Override
  public void onReceive(Context context, Intent intent) {  
    new MyAsyncTask.execute();
  }
}

发生警报时AlarmReceiver starts MyAsyncTask.

这里有龙

有生命周期问题 https://stackoverflow.com/questions/25174226/is-instantiating-an-asynctask-from-a-wakefulbroadcastreceiver-recommended与实例化相关联AsyncTask from a WakefulBroadcastReceiver，即上述解决方案可以导致MyAsyncTask过早地被杀死。而且，违反了线程规则 https://stackoverflow.com/a/25172977/3664487.