从ini文件中读取数据

我有一个需要输入文件名的 vbscript

代码是

 Dim tsout: Set tsout = gofs.CreateTextFile("C:\....csv")
 Dim tsin: Set tsin = gofs.OpenTextFile("C:\.....csv")

我该如何配置这个路径createTextFile(....)从配置文件中读取（.ini)

用于创建和写入输出的文件路径必须取自ini file

这是我的 ini 文件

//我的ini文件

[Read_file]
tsout=E:.....tt.csv
tsin=E:\....gt.csv

    [col]
Number1=4
Number2=5

.ini 文件解析器的简单版本：

Option Explicit

Dim goFS : Set goFS = CreateObject("Scripting.FileSystemObject")

'WScript.Quit demoReadFile()
WScript.Quit demoReadIniFile()

Function demoReadFile()
  demoReadFile = 0
  Dim tsIn : Set tsIn = goFS.OpenTextFile(".\21825192.ini")
  Do Until tsIn.AtEndOfStream
     Dim sLine : sLine = tsIn.ReadLine()
     WScript.Echo tsIn.Line - 1, sLine
  Loop
  tsIn.Close
End Function

Function demoReadIniFile()
  demoReadIniFile = 0
  Dim dicIni : Set dicIni = ReadIniFile(".\21825192.ini")
  Dim sSec, sKV
  For Each sSec In dicIni.Keys()
      WScript.Echo "---", sSec
      For Each sKV In dicIni(sSec).Keys()
          WScript.Echo " ", sKV, "=>", dicIni(sSec)(sKV)
      Next
  Next
  WScript.Echo dicIni("tsout")("Path")
End Function

Function ReadIniFile(sFSpec)
  Dim dicTmp : Set dicTmp = CreateObject("Scripting.Dictionary")
  Dim tsIn   : Set tsIn   = goFS.OpenTextFile(sFSpec)
  Dim sLine, sSec, aKV
  Do Until tsIn.AtEndOfStream
     sLine = Trim(tsIn.ReadLine())
     If "[" = Left(sLine, 1) Then
        sSec = Mid(sLine, 2, Len(sLine) - 2)
        Set dicTmp(sSEc) = CreateObject("Scripting.Dictionary")
     Else
        If "" <> sLine Then
           aKV = Split(sLine, "=")
           If 1 = UBound(aKV) Then
              dicTmp(sSec)(Trim(aKV(0))) = Trim(aKV(1))
           End If
        End If
     End If
  Loop
  tsIn.Close
  Set ReadIniFile = dicTmp
End Function

output:

cscript 21825192.vbs
1 [pipapo]
2 Path=E:\dont\find\me.csv
3   Some  = thing else
4
5 [tsout]
6 Path=E:\where\ever\output.csv
7 abc=def

cscript 21825192.vbs
--- pipapo
  Path => E:\dont\find\me.csv
  Some => thing else
--- tsout
  Path => E:\where\ever\output.csv
  abc => def
E:\where\ever\output.csv

(see 这个答案 https://stackoverflow.com/a/21758109/603855作为背景）

更新评论/编辑：

我将您的部分添加到我的示例 .ini 文件中：

type 21825192.ini
[pipapo]
Path=E:\dont\find\me.csv
  Some  = thing else

[tsout]
Path=E:\where\ever\output.csv
abc=def

[Read_file]
tsout=E:.....tt.csv
tsin=E:\....gt.csv

    [col]
Number1=4
Number2=5

并且 - 为了清楚起见 - 将 demoReadIniFile() 函数的最终输出行更改为：

  WScript.Echo "tsout.Path", dicIni("tsout")("Path")
  WScript.Echo "Read_file.tsin", dicIni("Read_file")("tsin")
  WScript.Echo "col.Number2", dicIni("col")("Number2")

输出：

cscript 21825192.vbs
--- pipapo
  Path => E:\dont\find\me.csv
  Some => thing else
--- tsout
  Path => E:\where\ever\output.csv
  abc => def
--- Read_file
  tsout => E:.....tt.csv
  tsin => E:\....gt.csv
--- col
  Number1 => 4
  Number2 => 5
tsout.Path E:\where\ever\output.csv
Read_file.tsin E:\....gt.csv
col.Number2 5

所以我根本不明白为什么访问“取出数字 1=4 和数字 2=5 的 col 部分”会导致任何问题。