未填充方块的 Matplotlib 散点图

我想制作一个带有未填充方块的散点图。markerfacecolor不是一个被认可的选项scatter https://matplotlib.org/devdocs/api/_as_gen/matplotlib.pyplot.scatter.html。我制造了一个MarkerStyle但散点图似乎忽略了填充样式。有没有办法在散点图中制作未填充的标记？

import matplotlib.markers as markers
import matplotlib.pyplot as plt 
import numpy as np

def main():
    size = [595, 842] # in pixels
    dpi = 72. # dots per inch
    figsize = [i / dpi for i in size]
    fig = plt.figure(figsize=figsize)
    ax = fig.add_axes([0,0,1,1])

    x_max = 52
    y_max = 90
    ax.set_xlim([0, x_max+1])
    ax.set_ylim([0, y_max + 1]) 

    x = np.arange(1, x_max+1)
    y = [np.arange(1, y_max+1) for i in range(x_max)]

    marker = markers.MarkerStyle(marker='s', fillstyle='none')
    for temp in zip(*y):
        plt.scatter(x, temp, color='green', marker=marker)

    plt.show()

main()

看来如果你想使用plt.scatter()那么你必须使用facecolors = 'none'而不是设置fillstyle = 'none'在建设中MarkerStyle, e.g.

marker = markers.MarkerStyle(marker='s')
for temp in zip(*y):
    plt.scatter(x, temp, color='green', marker=marker, facecolors='none')

plt.show()

or, use plt.plot() with fillstyle = 'none' and linestyle = 'none'但自从marker关键字在plt.plot不支持MarkerStyle您必须内联指定样式的对象，即

for temp in zip(*y):
    plt.plot(x, temp, color='green', marker='s', fillstyle='none')

plt.show()

其中任何一个都会给你看起来像这样的东西