我有一个日期列（称为“时间”），其中包含天/小时/分钟等（timedelta）。我在数据框中创建了一个新列，我想创建一个新列，并将“时间”列转换为秒。
我确实找到了如何转换列。如何根据现有 timedelta 列的秒数转换创建新的？
我想你需要total_seconds http://pandas.pydata.org/pandas-docs/stable/generated/pandas.Series.dt.total_seconds.html:
print (df['col'].dt.total_seconds())
Sample:
df = pd.DataFrame({'date1':pd.date_range('2015-01-01', periods=3),
'date2':pd.date_range('2015-01-01 02:00:00', periods=3, freq='23H')})
print (df)
date1 date2
0 2015-01-01 2015-01-01 02:00:00
1 2015-01-02 2015-01-02 01:00:00
2 2015-01-03 2015-01-03 00:00:00
df['diff'] = df['date2'] - df['date1']
df['seconds'] = df['diff'].dt.total_seconds()
print (df)
date1 date2 diff seconds
0 2015-01-01 2015-01-01 02:00:00 02:00:00 7200.0
1 2015-01-02 2015-01-02 01:00:00 01:00:00 3600.0
2 2015-01-03 2015-01-03 00:00:00 00:00:00 0.0
df['diff'] = df['date2'] - df['date1']
df['diff'] = df['diff'].dt.total_seconds()
print (df)
date1 date2 diff
0 2015-01-01 2015-01-01 02:00:00 7200.0
1 2015-01-02 2015-01-02 01:00:00 3600.0
2 2015-01-03 2015-01-03 00:00:00 0.0
如果需要投射到int:
df['diff'] = df['date2'] - df['date1']
df['diff'] = df['diff'].dt.total_seconds().astype(int)
print (df)
date1 date2 diff
0 2015-01-01 2015-01-01 02:00:00 7200
1 2015-01-02 2015-01-02 01:00:00 3600
2 2015-01-03 2015-01-03 00:00:00 0
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