from datetime import datetime
excel_date = 42139
dt = datetime.fromordinal(datetime(1900, 1, 1).toordinal() + excel_date - 2)
tt = dt.timetuple()
print(dt)
print(tt)
正如 J.F. Sebastian 所提到的,此答案仅适用于 1900/03/01 之后的任何日期
编辑:(回答@R.K)
If your excel_date
是一个浮点数,使用以下代码:
from datetime import datetime
def floatHourToTime(fh):
hours, hourSeconds = divmod(fh, 1)
minutes, seconds = divmod(hourSeconds * 60, 1)
return (
int(hours),
int(minutes),
int(seconds * 60),
)
excel_date = 42139.23213
dt = datetime.fromordinal(datetime(1900, 1, 1).toordinal() + int(excel_date) - 2)
hour, minute, second = floatHourToTime(excel_date % 1)
dt = dt.replace(hour=hour, minute=minute, second=second)
print(dt)
assert str(dt) == "2015-05-15 00:13:55"