从数据库中删除重复项的脚本[关闭]

我有一个数据库，其中有电话号码、组织、公司名称、邮政编码等数据。

我的数据库中也有一些重复项，例如相同的公司名称、相同的组织、相同的邮政编码但不同的相同电话号码。所以我想通过使用脚本删除这些重复项。我怎样才能写出这样的脚本？

CREATE TABLE TEST (
    address_id        bigint,
    name              varchar(255),
    marketing_name    varchar(255),
    co_address        varchar(255),
    box_address1      varchar(255),
    box_address2      varchar(255),
    box_postal_code   varchar(45),
    visit_address1    varchar(255),
    org_nr            varchar(255),
    visit_postal_code varchar(255),
    county_id         varchar(255),
    contact           varchar(255),
    complete          tinyint,
    deleted           tinyint,
    district_id       varchar(255),
    region            varchar(255),
    phone1            varchar(255),
    mobile_phone      varchar(255),
)

首先，您需要决定要使用的重复标准是什么。例如，我想检查同一组织名称、公司名称和邮政编码中的电话号码是否重复。我可以做这个：

第一个测试表

CREATE TABLE TEST
(
id int,
phonenumber int,
orgno int,
companyname varchar(100),
postalcode varchar(4)
)

然后测试数据

  insert into TEST
 values (1,4533660,1,'COMPANY 1',1234)
  insert into TEST
 values (2,4533660,1,'COMPANY 1',1234)
  insert into TEST
 values (3,954189547,1,'COMPANY 2',4444)
   insert into TEST
 values (4,954189547,1,'COMPANY 2',4444)
   insert into TEST
 values (5,3652591,1,'COMPANY 3',4444)
   insert into TEST
 values (6,4201580,1,'COMPANY 4',4444)
   insert into TEST
 values (7,3337788,1,'COMPANY 5',4444)

最后，使用选定的条件查询重复项。

 Select phonenumber,
 orgno,
 companyname,
 postalcode,
 COUNT(*)
 from test 
 group by phonenumber,
 orgno, 
 companyname,
 postalcode 
 HAVING COUNT(*) > 1

通过此查询，您可以轻松找到重复项，最重要的是检查重复项的条件。

Edit

如果要删除除 1 之外的所有重复行，可以这样做：

DELETE A
FROM TEST A 
INNER JOIN 
(
        SELECT ROW_NUMBER()OVER(PARTITION BY a.phonenumber,
        a.orgno,
        a.companyname,
        a.postalcode ORDER BY a.id)AS POS,
        a.phonenumber,
        a.orgno,
        a.companyname,
        a.postalcode,
        a.id
        FROM TEST A
        JOIN 
        (
                SELECT  
                phonenumber,
                orgno,
                companyname,
                postalcode,
                COUNT(*) AS CONTADOR
                FROM test 
                GROUP BY phonenumber,
                orgno, 
                companyname,
                postalcode
                HAVING COUNT(*) > 1
        ) TB
        ON A.companyname = TB.companyname 
        AND A.orgno = TB.orgno 
        AND A.phonenumber = TB.phonenumber 
        AND A.postalcode = TB.postalcode
) TB_2
ON
a.id = tb_2.id 
and tb_2.pos > 1

使用提供的数据结构编辑脚本。

DELETE FROM TEST B
JOIN 
(
    SELECT ROW_NUMBER()OVER(PARTITION BY
    a.org_nr,
    a.phone1,
    a.phone2,
    a.name,
    a.marketing_name
    ORDER BY 
    a.org_nr,
    a.phone1,
    a.phone2,
    a.name,
    a.marketing_name
    )AS POS,
    a.address_id,
    a.org_nr,
    a.phone1,
    a.phone2,
    a.name,
    a.marketing_name
    FROM TEST A
    JOIN 
    (
        SELECT 
        org_nr,
        phone1,
        phone2,
        name,
        marketing_name
        FROM TEST 
        GROUP BY 
        org_nr,
        phone1,
        phone2,
        name,
        marketing_name
        HAVING COUNT(*) > 1) TB
        ON a.org_nr = tb.org_nr
        and a.phone1 = tb.phone1
        and a.phone2 = tb.phone2
        and a.name = tb.name
        and a.marketing_name = tb.marketing_name
    ) TB_2
ON
b.address_id = tb_2.address_id
and tb_2.pos > 1