如何在日期时间中支持bigint

的结果datediff(ss, '01/01/1970', '12/31/2050') is a bigint so datediff已经满溢了。

我怎样才能从bigint如果 SQL 中日期的最大值为，则返回其等效日期并再次返回int?

我需要能够存储之间的秒数01/01/1970 and 12/31/2050在 SQL 中（我将其作为char），但将该值转换为其日历日期以在网页中显示。

任何想法，将不胜感激。

谢谢你！

这会给你毫秒。轻松适应秒...

declare @dfrom datetime = '1970-01-01 16:15:33.021'
declare @dto datetime = '2058-01-01 15:00:55.557'

declare @diff bigint = 
    cast(DATEDIFF(d, @dfrom, @dto) as bigint) * 24 * 3600 * 1000 
     + DATEDIFF(ms, cast(@dfrom as time), cast(@dto as time))    

declare @dreverse datetime = 
    dateadd(ms, @diff % (1000 * 3600 * 24), 
        dateadd(day, @diff / (1000 * 3600 * 24), @dfrom))   

select @dfrom as [From], @dto as [To], @diff as [Diff], @dreverse as [Reverse] for xml path('')

gives:

<From>1970-01-01T16:15:33.020</From>
<To>2058-01-01T15:00:55.557</To>
<Diff>2777064322537</Diff>
<Reverse>2058-01-01T15:00:55.557</Reverse>