在 HashMap 或 LinkedList 中将嵌套类设为静态的原因是什么？ [复制]

在大多数情况下，我看到嵌套类是static.

让我们举个例子Entry上课于HashMap

static class Entry<K,V> implements Map.Entry<K,V> {
    final K key;
    V value;
    Entry<K,V> next;
    final int hash;

    .....
    .....
}

Or Entry类的LinkedList

private static class Entry<E> {
    E element;
    Entry<E> next;
    Entry<E> previous;

    .....
    .....
}

到目前为止我对嵌套类的了解是：

- A non-static nested class has full access to the members of the class 
  within which it is nested.

- A static nested class cannot invoke non-static methods or access non-
  static fields

我的问题是，在 HashMap 或 LinkedList 中将嵌套类设为静态的原因是什么？

更新1：

Following the already answer link I got an answer - Since And since it does not need 
access to LinkedList's members, it makes sense for it to be static - it's a much 
cleaner approach.

Also as @Kayaman pointed out: A nested static class doesn't require an instance of 
the enclosing class. This means that you can create a HashMap.Entry by itself, 
without having to create a HashMap first (which you might not need at all).

我认为这两点都回答了我的问题。感谢大家的意见。

嵌套静态类不需要封闭类的实例。这意味着您可以创建一个HashMap.Entry本身，无需创建HashMap首先（您可能根本不需要）。