我试图从给定 XML 文件中的特定元素查找给定 XML 元素的相对深度,我尝试使用 XPATH,但我对 XML 解析不太熟悉,并且没有得到所需的结果。我还需要在计数时忽略数据元素。
下面是我编写的代码和示例 XML 文件。
例如。的深度NM109_BillingProviderIdentifier
from TS837_2000A_Loop
元素为4。
父节点是:TS837_2000A_Loop < NM1_SubLoop_2 < TS837_2010AA_Loop < NM1_BillingProviderName
as NM109_BillingProviderIdentifier
是一个孩子NM1_BillingProviderName
因此相对深度NM1_BillingProviderName
from TS837_2000A_Loop
为 4(包括TS837_2000A_Loop
).
package com.xmlexamples;
import java.io.File;
import java.io.FileInputStream;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
public class XmlParser {
public static void main(String[] args) throws Exception {
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setValidating(false);
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new FileInputStream(new File("D://sample.xml")));
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
String expression;
expression = "count(NM109_BillingProviderIdentifier/preceding-sibling::TS837_2000A_Loop)+1";
Double d = (Double) xpath.compile(expression).evaluate(doc, XPathConstants.NUMBER);
System.out.println("position from TS837_2000A_Loop " + d);
}
}
<?xml version='1.0' encoding='UTF-8'?>
<X12_00501_837_P xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<TS837_2000A_Loop>
<NM1_SubLoop_2>
<TS837_2010AA_Loop>
<NM1_BillingProviderName>
<NM103_BillingProviderLastorOrganizationalName>VNA of Cape Cod</NM103_BillingProviderLastorOrganizationalName>
<NM109_BillingProviderIdentifier>1487651915</NM109_BillingProviderIdentifier>
</NM1_BillingProviderName>
<N3_BillingProviderAddress>
<N301_BillingProviderAddressLine>8669 NORTHWEST 36TH ST </N301_BillingProviderAddressLine>
</N3_BillingProviderAddress>
</TS837_2010AA_Loop>
</NM1_SubLoop_2>
</TS837_2000A_Loop>
</X12_00501_837_P>
获取任何节点深度的关键方法是计算其祖先(包括父节点、父节点的父节点等):
count(NM109_BillingProviderIdentifier/ancestor-or-self::*)
这将为您提供一直到根的计数。为了得到relative计数,即从根以外的任何位置,假设名称不重叠,您可以这样做:
count(NM109_BillingProviderIdentifier/ancestor-or-self::*)
- count(NM109_BillingProviderIdentifier/ancestor::TS837_2000A_Loop/ancestor::*)
根据当前元素或基本元素是否应包含在计数中,使用ancestor-or-self
or ancestor
axis.
PS:你可能应该感谢彼得罗·萨卡尔迪 https://stackoverflow.com/users/1749822/pietro-saccardi非常感谢您的帖子和巨大的(一行 4kB..)示例 XML 可读。
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