我有一群候选人,他们都做过一份或多份工作,每个人都有一家公司,使用一些技能。
糟糕的 ASCII 艺术如下:
--------------- ---------------
| candidate 1 | | candidate 2 |
--------------- \ --------------
/ \ |
------- -------- etc
|job 1| | job 2 |
------- ---------
/ \ / \
--------- --------- --------- --------
|company | | skills | |company | | skills |
--------- --------- ---------- ----------
这是我的数据库:
mysql> describe jobs;
+--------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+---------+------+-----+---------+----------------+
| job_id | int(11) | NO | PRI | NULL | auto_increment |
| candidate_id | int(11) | NO | MUL | NULL | |
| company_id | int(11) | NO | MUL | NULL | |
| start_date | date | NO | MUL | NULL | |
| end_date | date | NO | MUL | NULL | |
+--------------+---------+------+-----+---------+----------------+
.
mysql> describe candidates;
+----------------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------+----------+------+-----+---------+----------------+
| candidate_id | int(11) | NO | PRI | NULL | auto_increment |
| candidate_name | char(50) | NO | MUL | NULL | |
| home_city | char(50) | NO | MUL | NULL | |
+----------------+----------+------+-----+---------+----------------+
.
mysql> describe companies;
+-------------------+---------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------+---------------+------+-----+---------+----------------+
| company_id | int(11) | NO | PRI | NULL | auto_increment |
| company_name | char(50) | NO | MUL | NULL | |
| company_city | char(50) | NO | MUL | NULL | |
| company_post_code | char(50) | NO | | NULL | |
| latitude | decimal(11,8) | NO | | NULL | |
| longitude | decimal(11,8) | NO | | NULL | |
+-------------------+---------------+------+-----+---------+----------------+
.
mysql> describe skills;
+----------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------+---------+------+-----+---------+-------+
| skill_id | int(11) | NO | MUL | NULL | |
| job_id | int(11) | NO | MUL | NULL | |
+----------+---------+------+-----+---------+-------+
.
mysql> describe skill_names;
+------------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+----------+------+-----+---------+----------------+
| skill_id | int(11) | NO | PRI | NULL | auto_increment |
| skill_name | char(32) | NO | MUL | NULL | |
+------------+----------+------+-----+---------+----------------+
这是我的查询尝试(注意,我打算将通配符更改为字段名称;我只是想让某些东西起作用):
SELECT can.* , co.*, j.*, sn.*
FROM candidates AS can
JOIN jobs AS j
JOIN companies AS co ON j.company_id = co.company_id
JOIN skills AS s ON s.job_id = j.job_id
JOIN skill_names AS sn ON s.skill_id = s.skill_id
海蒂SQL 说/* Affected rows: 0 Found rows: 34,461,651 Warnings: 0 Duration for 1 query: 0.000 sec. (+ 105.078 sec. network) */
查询出了什么问题?我希望从糟糕的 ASCII 艺术中可以清楚地看出我想要实现的目标。
(另外,我加入表的顺序是否有任何速度差异?我会担心新的 MySql v8 函数稍后将其作为嵌套 JSON 检索)