如何用笛卡尔绘制波纹圆？

I'm looking for a way to plot a corrugated circle https://www.mypandakitchen.com/1656-large_default/emporte-pieces-rond-ondule.jpg in Python. My attempt doesn't produce the correct output:

from matplotlib import pyplot as plt
import numpy as np
from math import pi

x=np.linspace(-10,10,100)
y=x

X, Y = np.meshgrid(x,y)

circle = (X-np.cos(2*pi*0.2*Y))**2 + (Y-np.sin(2*pi*0.2*X))**2 - 5.

plt.contour(X,Y,circle,[0])
plt.show()

theta = np.linspace(-pi,pi,100)
courbure = np.sin(theta*10)

plt.plot(theta,courbure)
plt.show()
    
circle2 = (X-(courbure*np.cos(theta)))**2 + (Y-np.sin(theta)*courbure)**2 - courbure**2
plt.contour(X,Y,circle2)
plt.show()

谢谢。

我使用频率等于 10 的正弦波绘制了一个波纹圆。半径在 0.9 和 1 之间振荡。因为我取正弦的负绝对部分。幅度除以 10。

为了增加波纹，您必须增加频率。 这里f=10。

from matplotlib import pyplot as plt
import numpy as np
from math import pi

x=np.linspace(-10,10,1000)
y=x

X, Y = np.meshgrid(x,y)

circle = (X)**2 + (Y)**2 - (1+ -np.abs(np.sin(np.arctan(Y/X)*10))/10)

plt.contour(X,Y,circle)
plt.show()