当前有一系列包含游戏版本的对象。然而,游戏发布可以在多个平台上进行,并且这些平台在数组中显示为单独的对象。我希望通过比较游戏 ID 来删除重复的游戏,但合并平台对象
我尝试过使用reduce函数,它成功地通过游戏id删除了重复的对象,但我无法适应合并平台
const filteredArr = data.reduce((acc, current) => {
const x = acc.find(item => item.game.id === current.game.id);
if (!x) {
return acc.concat([current]);
} else {
return acc;
}
}, []);
当前数组:
const data = [{
"id": 157283,
"date": 1553212800,
"game": {
"id": 76882,
"name": "Sekiro: Shadows Die Twice",
"popularity": 41.39190295640344
},
"human": "2019-Mar-22",
"m": 3,
"platform": {"id": 48, "name": "PlayStation 4"},
"region": 8,
"y": 2019
}, {
"id": 12,
"date": 1553212800,
"game": {
"id": 76832,
"name": "Spiderman",
"popularity": 41.39190295640344
},
"human": "2019-Mar-22",
"m": 3,
"platform": {"id": 6, "name": "PC (Microsoft Windows)"},
"region": 8,
"y": 2019
}, {
"id": 157283,
"date": 1553212800,
"game": {
"id": 76882,
"name": "Sekiro: Shadows Die Twice",
"popularity": 41.39190295640344
},
"human": "2019-Mar-22",
"m": 3,
"platform": {"id": 48, "name": "Xbox"},
"region": 8,
"y": 2019
}]
合并后的预期格式:
[{
"id": 157283,
"date": 1553212800,
"game": {
"id": 76882,
"name": "Sekiro: Shadows Die Twice",
"popularity": 41.39190295640344
},
"human": "2019-Mar-22",
"m": 3,
"platforms": ["PlayStation", "Xbox"],
"region": 8,
"y": 2019
}, {
"id": 12,
"date": 1553212800,
"game": {
"id": 76832,
"name": "Spiderman",
"popularity": 41.39190295640344
},
"human": "2019-Mar-22",
"m": 3,
"platforms": ["Playstation"],
"region": 8,
"y": 2019
}]