Laravel include 导致错误：Method Illuminate\View\View::__toString() 不得抛出异常

我在 laravel 中包含一个文件，它向我抛出以下错误：

Method Illuminate\View\View::__toString() must not throw an exception

我已将文件包含在内：

@include('users.opentasks')

我在同一页面上使用两个包含，但如果我使用一个，则没有什么区别。

我不太确定这意味着什么以及如何解决这个新手问题。希望有人能帮忙。

我的代码如下：

用户控制器.php

public function profile() {
     $status = "closed";
    $data["projects"] = $projects = Auth::user()->projects()->where('status', '!=', $status) 
                                ->paginate(4);

    //$data["tasks"] = $tasks = Auth::user()->tasks->paginate(4);

      //  $data["tasks_pages"] = $tasks->links();

        //Comments pagination
        $data["projects_pages"] = $projects->links();


         if(Request::ajax())
            {

            $html = View::make('users.openprojects', $data)->render();
            return Response::json(array('html' => $html));
        //    $html = View::make('users.opentasks', $data)->render();
          //  return Response::json(array('html' => $html));
        }

        echo View::make('users.profile')->with('projects', $projects);

}

public function opentasks() { 

            $user = User::with(array('tasks', 'tasks.status'))->find(Auth::user()->id); 
            return View::make('users.opentasks')->with('user', $user); 

}

配置文件.blade.php

@extends("layout")
@section("content")
@include('users.openprojects')
@include('users.opentasks')
@stop

opentasks.blade.php

@foreach($user->tasks as $task) 
    {{ $task->task_name }} 
    {{ $task->task_brief}} 
            @if(!is_null($task->status)) 
              {{ $task->status->status_name }}<br/><br/><br/><br/> 
            @endif 
@endforeach

你可能想这样做：

if(Request::ajax())
{
  // --- this part of the code is odd
  $html = View::make('users.openprojects', $data)->render();
  return Response::json(array('html' => $html));
  // ---
} else {
  $user = User::with(array('tasks', 'tasks.status'))->find(Auth::user()->id); 

  $data = array(
     'user'     => $user,
     'projects' => $projects
  );

  return View::make('users.profile', $data);
}