如何使用 Python IMAP 从 Gmail 邮件中删除“来自无人”和“内容类型”？

尽管我在从很多网站进行大量搜索后完成了大部分工作，但我仍然无法获得我想要的正确输出。

Code:

import imaplib

import smtplib

import email

mail=imaplib.IMAP4_SSL("imap.gmail.com")

mail.login("**************@gmail.com","********")

mail.select('inbox')

type,data=mail.search(None,'ALL')

mail_ids=data[0]

id_list=mail_ids.split()

for i in range(int(id_list[-1]),int(id_list[0])-1,-1):
    
    typ,data=mail.fetch(i,'(RFC822)') 
        for response_part in data :
            if isinstance(response_part,tuple):
                msg=email.message_from_string(response_part[1])
                email_from=msg['from']
                email_subj=msg['subject']
                c=msg.get_payload(0)
                print email_from
                print "subj:",email_subj
                print c

Output:

Bharath Joshi <[email protected] /cdn-cgi/l/email-protection> subj: hehe From nobody Tue
Dec 25 15:48:52 2018 Content-Type: text/plain; charset="UTF-8"

hello444444444

Bharath Joshi <[email protected] /cdn-cgi/l/email-protection> subj:  From nobody Tue Dec 25
15:48:52 2018 Content-Type: text/plain; charset="UTF-8"

33333

Bharath Joshi <[email protected] /cdn-cgi/l/email-protection> subj:  From nobody Tue Dec 25
15:48:53 2018 Content-Type: text/plain; charset="UTF-8"

hello--22

困扰我的是我得到的额外的东西，即

“没有人......”和“内容类型......”

我怎样才能将它们删除？

啊，电子邮件的“美丽”......显然您面临着多部分电子邮件，对于这些，get_payload()方法还输出标题。你需要使用msg.walk()像这样：

for response_part in data :
    if isinstance(response_part,tuple):
        msg=email.message_from_string(response_part[1])
        print "subj:", msg['subject']
        print "from:", msg['from']
        print "body:"
        for part in msg.walk():
            if part.get_content_type() == 'text/plain':
                print part.get_payload()

要获得更完整的答案，请查看这个 stackoverflow 答案 https://stackoverflow.com/questions/1463074/how-can-i-get-an-email-messages-text-content-using-python