在Python中使用循环从列表中弹出项目[重复]

我正在尝试在 python 中编写一个 for 循环来弹出列表中除两个之外的所有项目，所以我尝试了以下方法：

guest = ['john', 'phil', 'andy', 'mark', 'frank', 'joe']

for people in guest:
    popped_guest = guest.pop()
    print("I am sorry " + popped_guest + " I can no longer invite you to dinner")

而且，这就是我运行它时得到的结果：

I am sorry joe I can no longer invite you to dinner

I am sorry frank I can no longer invite you to dinner

I am sorry mark I can no longer invite you to dinner

所以，它只弹出 3 个，但有没有办法让它弹出 6 个中的 4 个呢？我尝试添加一个 if 语句：

guest = ['john', 'phil', 'andy', 'mark', 'frank', 'joe']

for people in guest:
    if people > guest[1]:
        popped_guest = guest.pop()
        print("I am sorry " + popped_guest + " I can no longer invite you to dinner")

我本以为“phil”是 1，它会弹出最后 4 个，但当我运行该程序时，它什么也没返回。那么，是否可以在一个for循环中完成呢？

如果你想弹出 4 个东西，那么就数到 4

for _ in range(4):
    popped_guest = guest.pop()
    print("I am sorry " + popped_guest + " I can no longer invite you to dinner")