使用C打开目录

我接受通过命令行输入的路径。

当我做

dir=opendir(args[1]);

它不会进入循环...即dir==null...

如何将命令行输入传递给 dir 指针？

void main(int c,char **args)
{
    DIR *dir;
    struct dirent *dent;
    char buffer[50];
    strcpy(buffer, args[1]);
    dir = opendir(buffer);   //this part
    if(dir!=NULL)
    {
        while((dent=readdir(dir))!=NULL)
            printf(dent->d_name);
    }
    close(dir);
}

./a.out  /root/TEST is used to run the program..
./a.out --> to execute the program
/root/TEST --> input by the user i.e valid path

You should really post your code^(a), but here goes. Start with something like:

    #include <stdio.h>
    #include <dirent.h>

    int main (int argc, char *argv[]) {
        struct dirent *pDirent;
        DIR *pDir;

        // Ensure correct argument count.

        if (argc != 2) {
            printf ("Usage: testprog <dirname>\n");
            return 1;
        }

        // Ensure we can open directory.

        pDir = opendir (argv[1]);
        if (pDir == NULL) {
            printf ("Cannot open directory '%s'\n", argv[1]);
            return 1;
        }

        // Process each entry.

        while ((pDirent = readdir(pDir)) != NULL) {
            printf ("[%s]\n", pDirent->d_name);
        }

        // Close directory and exit.

        closedir (pDir);
        return 0;
    }

您需要检查您的情况args[1]既已设置又引用实际目录。示例运行，tmp是我当前目录之外的子目录，但您可以使用任何有效的目录，给我： 测试程序临时文件

[.]
[..]
[file1.txt]
[file1_file1.txt]
[file2.avi]
[file2_file2.avi]
[file3.b.txt]
[file3_file3.b.txt]

另请注意，您必须通过目录在，不是一个file.当我执行时：

testprog tmp/file1.txt

I get:

Cannot open directory 'tmp/file1.txt'

这是因为它是一个文件而不是一个目录（不过，如果你偷偷摸摸，你可以尝试使用diropen(dirname(argv[1]))如果初始的diropen fails).

^(a) This has now been rectified but, since this answer has been accepted, I'm going to assume it was the issue of whatever you were passing in.