首先,我对 C# 和 Java 都是菜鸟。
因此,我被分配了将 java 小程序转换为 C# 的任务,除了使用鼠标事件通过拖放在屏幕上绘制矩形之外,我还成功完成了所有操作。
应该发生的情况是,当我单击鼠标并在屏幕上拖动鼠标时,应该会出现一个没有填充和白色边框的矩形。我下面的代码只是一个白色的屏幕,上面有一个红十字,如果我注释掉 form1_Paint 中的 if(action) 语句,那么它可以工作,但没有矩形,所以一定是那个代码搞乱了它。
http://gyazo.com/b2506b8c2ea9b304e34172c42ce98aab http://gyazo.com/b2506b8c2ea9b304e34172c42ce98aab
http://gyazo.com/a8764ac9f5380f0109623d7a7750ddb6 http://gyazo.com/a8764ac9f5380f0109623d7a7750ddb6
[update]
我现在有一个要显示的矩形,但它发生在 MouseUp 事件上,而不是在我拖动鼠标时创建它。显而易见的下一步是将其移动到不同的鼠标事件,例如 mouseMove,但当我将其变大时,它确实会变得混乱并不断创建矩形。如何让它在拖动鼠标时不断调整矩形大小而不是不断创建矩形?
代码
private void Form1_Paint(object sender, PaintEventArgs e)
{
Graphics g1 = e.Graphics;
g1.DrawImage(bitmap, 0, 0, x1, y1);
}
//added load method
private void Form1_Load(object sender, EventArgs e)//runs functions on load
{
init();
start();
}
private void Form1_MouseMove(object sender, MouseEventArgs e)
{
if (action)
{
xe = e.X;
ye = e.Y;
}
}
private void Form1_MouseDown(object sender, MouseEventArgs e)
{
action = true;
// e.consume();
xs = xe = e.X;
ys = ye = e.Y; // starting point y
Form1_MouseMove(sender, e);
this.Invalidate();
}
private void Form1_MouseUp(object sender, MouseEventArgs e)
{
using (Graphics g = this.CreateGraphics())
{
Pen pen = new Pen(Color.White);
g.DrawRectangle(pen, xs, ys, Math.Abs(xs - xe), Math.Abs(ys - ye));
}
int z, w;
//e.consume();
//xe = e.X;
//ye = e.Y;
if (xs > xe)
{
z = xs;
xs = xe;
xe = z;
}
if (ys > ye)
{
z = ys;
ys = ye;
ye = z;
}
w = (xe - xs);
z = (ye - ys);
if ((w < 2) && (z < 2)) initvalues();
else
{
if (((float)w > (float)z * xy)) ye = (int)((float)ys + (float)w / xy);
else xe = (int)((float)xs + (float)z * xy);
xende = xstart + xzoom * (double)xe;
yende = ystart + yzoom * (double)ye;
xstart += xzoom * (double)xs;
ystart += yzoom * (double)ys;
}
xzoom = (xende - xstart) / (double)x1;
yzoom = (yende - ystart) / (double)y1;
mandelbrot();
this.Invalidate();
//Repaint();
}